I think it’s B I could be wrong but I tried lol
En caso de una colisión de bajo nivel de gravedad podría golpearse con el tablero del carro o en la parte del sillón (si esta sentado en la parte trasera). Pero si es muy grave la colisión podría salirse del carro por el cristal.
A force field works the same as a shield. I protects what ever is inside, or behind the field.
Answer:
a)Taking into consideration Newton’s second law, we know that
Net_Force = mass * acceleration
Since the box is pulled at constant speed, the acceleration is equal to zero.
This means that
Net_Force = 0 N
b) Force of friction
The net force is equal to the sum of all forces,
Net_Force = Force_applied - Friction
We found that Net_Force = 0, which means
Friction = Force_applied = 48 N
c) If the box comes to a stop. And the applied force becomes zero, the friction force becomes also zero.
Friction = 0 N
Answer:
linear cart C Vs 1/R² or log cart C Vs R
Explanation:
Gamma radiation is very high energy electromagnetic rays, but its behavior is the same as for all radiation. By the principle of conservation of energy after the radiation is emitted, it must be distributed on a spherical surface which determines the behavior of the inverse of the square.
In this experiment you are measuring the rate of counts by time (C), this must be the dependent variable since it is not controlled by the experimenter and on the other hand it measures the distance (X) this is the independent variable since it is the one that we can control.
To make a graph with this data, the counting rate must be plotted against the inverse of the squared distance (1/R²). On the Y axis the counts per second and the X 1 / R² axis, with this graph a line must be obtained.
Another graph that we can make on double logarithmic paper where the Y axis plotted the counting rate and on the X axis the distance, the slope should give -2.
C == A / R²
Log C = log A -2 log R
With either of the two graphs, the law of the inverse of the square is tested
