The solution for this is:
Work done = force * distance = m*a*d and power = energy/time
The vo=0 and vf = 25 m/s and t=7 sec. This gives...
3.6 m/s^2 as acceleration and d=87.5 meters and thus F=ma= 5400 N.
Energy = 5400*87.5 = 4.7E5 Joules (2 sig. figs) and Power = 67,500 Watts or 90 HP (2 sig. figs again).
Answer:
3.83 m/s
Explanation:
Given that,
Distance covered by Jan, d = 4 miles
1 mile = 1609.34 m
4 miles = 6437.38 m
Time, t = 28 minutes = 1680 s
Jan's average speed,
v = d/t
Hence, the average velocity of Jan is 3.83 m/s.
Answer:
Option (D) On average, the molecules of gas 1 lose some of their kinetic energy to the molecules of gas 2 through collisions, resulting in the two gases eventually having the same temperature.
Explanation:
From the question given, Gas 1 was initially at a higher temperature than Gas 2.
As the two gas mixes together, there will be a transfer of heat from Gas 1 molecules to Gas 2 molecules. Now, as this continues over a period of time, the two gas will eventually have the same temperature.
What fraction of stipend triangle is a shaded triangle? What fraction of the spotted triangle is a shaded triangle? Use >,
