Question

How many moles of agcl are contained in 244 ml of 0.135 magcl solution? the density of the solution is 1.22 g/ml?

Answer 1

Since we are only asked for the number of moles, we don't need the information of density. The concentration is expressed in terms of 0.135 M AgCl or 0.135 moles of AgCl per liter solution. The solution is as follows:

Moles AgCl = Molarity * Volume
Moles AgCl = 0.135 mol/L * 244 mL * 1 L/1000 mL
Moles AgCl = 0.03294 mol 

Answer 2

Answer: The moles of AgCl contained in the solution is 0.033 moles

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}$

Molarity of AgCl solution = 0.135 M

Volume of solution = 244 mL

Putting values in above equation, we get:

$0.135M=\frac{\text{Moles of AgCl}\times 1000}{244}\\\\\text{Moles of AgCl}=\frac{0.135\times 244}{1000}=0.033mol$

Hence, the moles of AgCl contained in the solution is 0.033 moles