Question

CHEMISTRY! 50 POINTS! What is the original pressure of 20.0L of compressed gas if the pressure changes to 560.0mmHg when the volume is decreased to 15700mL?

Answer 1

Answer:

The answer is 439.60 mmHg

Explanation:

To find the original pressure we use the formula for Boyle's law which is

$P_1V_1 = P_2V_2$

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we are finding the original pressure

$P_1 = \frac{P_2V_2}{V_1}$

From the question

V1 = 20 L = 20,000 mL

P2 = 560.0mmHg

V2 = 15700mL

We have

$P_1 = \frac{560 \times 15700}{20000} = \frac{8792000}{20000} = \frac{2198}{5 }$

We have the final answer as

439.60 mmHg

Hope this helps you