Answer:
1-bromo-6-chloro-5-methylheptane
Explanation:
There are 3 substituents, 1 chlorine, 1 bromine, and 1 methyl group.
The longest carbon chain consists of 7 carbons.
There are no double bonds, based on the saturation and substituents.
So you have a 1-bromo-6-chloro-5-methylheptane.
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The atmosphere of earth is made of five main layers.
1) Troposphere : This is the lowest part of the atmosphere. Most of the air that makes up the atmosphere is present in this layer.
2) Stratosphere : This layer is present above troposphere and extends up to 50 km. It contains ozone layer which prevents the harmful ultraviolet rays from the sun from entering the lower troposphere
3) Mesosphere : The layer above stratosphere is known as mesosphere.
4) Thermosphere : The region lies above mesosphere.
5) Exosphere : The is the outermost region of the atmosphere.
From the above discussion we can see that the layer that lies between exosphere and mesosphere is Thermosphere
D represents ion-dipole forces that are stronger than the force C.
Explanation:
D represents the ion-dipole force.
C represents the H-bonding forces.
ion-dipole force is a force that is due to electrostatic attraction and has a dipole between an ion and a neutral molecule.
It is electrostatic in nature.
A hydrogen bond is the force between the hydrogen with the electro negative atom of one molecule, to electro negative atom of some other molecule. such as: O, F, N
Ion dipole force is stronger than the H-bonding.
The value of log₂(x/4) is 22. Using the properties of the logarithm, the required value is calculated.
<h3>What are the required properties of the logarithm?</h3>
The required logarithm properties are
logₐx = n ⇒ aⁿ = x; and logₐ(xⁿ) = n logₐ(x);
Where a is the base of the logarithm.
<h3>Calculation:</h3>
It is given that,
log₄(x) = 12;
On applying the property logₐx = n ⇒ aⁿ = x; here a = 4;
So,
log₄(x) = 12 ⇒ 4¹² = x
⇒ x = (2²)¹² = 2²⁴
Then, calculating log₂(x/4):
log₂(x/4) = log₂(2²⁴/4)
= log₂(2²⁴/2²)
= log₂(2²⁴ ⁻ ²)
= log₂(2²²)
On applying the property logₐ(xⁿ) = n logₐ(x);
log₂(x/4) = 22 log₂2
We know that logₐa = 1;
So,
log₂(x/4) = 22(1)
∴ log₂(x/4) = 22.
Learn more about the properties of logarithm here:
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