Answer:
6.05 cm
Explanation:
The given equation is
2 aₓ(x-x₀)=( Vₓ²-V₀ₓ²)
The initial head velocity V₀ₓ =11 m/s
The final head velocity Vₓ is 0
The accelerationis given by =1000 m/s²
the stopping distance = x-x₀=?
So we can wind the stopping distance by following formula
2 (-1000)(x-x₀)=[
]
x-x₀=6.05*
m
=6.05 cm
Answer:
The units of the orbital period P is <em>years </em> and the units of the semimajor axis a is <em>astronomical units</em>.
Explanation:
P² = a³ is the simplified version of Kepler's third law which governs the orbital motion of large bodies that orbit around a star. The orbit of each planet is an ellipse with the star at the focal point.
Therefore, if you square the year of each planet and divide it by the distance that it is from the star, you will get the same number for all the other planets.
Thus, the units of the orbital period P is <em>years </em> and the units of the semimajor axis a is <em>astronomical units</em>.
Answer:
The radius of the curve is 9,183.67 m.
Explanation:
Given;
velocity of the jet plane, v = 600 m/s
acceleration of the jet plane, a = 4g = 4 x 9.8 m/s² = 39.2 m/s²
The radius of the curve is calculated from centripetal acceleration formula as given below;
Therefore, the radius of the curve is 9,183.67 m.
Answer:
Amplitude : The height of the wave from the origin to the crest/peak or trough
Explanation:
