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VashaNatasha [74]
2 years ago
6

PLEASE ANSWER NEED HELP!!!!!!!! PLEASE THE CORRECT ANSWER!!!!!!

Physics
2 answers:
mars1129 [50]2 years ago
5 0

D.

Exercise reduces stress and boosts confidence, which can create positive change.

k0ka [10]2 years ago
5 0
The answer is D exercise reduces stress and boosts confidence which can create positive change. lmk if this helps
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A light bulb radiates 110 nW of single-frequency sinusoidal electromagnetic waves uniformly in all directions. Calculate the ave
krek1111 [17]

Answer:

The intensity of the light from the bulb would be

3.501 x 10^{-6} W/m^{2}

Explanation:

Given

The Power = 110 n W = 110 x 10^{-9} W

the distance r = 50 mm = 50 /1000 = 0.05 m

The intensity can be obtained with the relationship below;

I = Power/area ......1

The area of the sphere would be used in this case since the bulb is spherical;    A=4πr^{2}

Putting it into equation 1, we have;

I = P/ 4πr^{2}

I =  110 x 10^{-9} / 4 x π x 0.05^{2}

I = 3.501 x 10^{-6} W/m^{2}

Therefore the intensity of the light from the bulb would be

3.501 x 10^{-6} W/m^{2}

6 0
3 years ago
Which item is an example of a primary source? A. An academic paper analyzing John F. Kennedy's presidency B. A transcript of a p
Viktor [21]

A transcript of a presidential speech (APEX Class ;)

7 0
3 years ago
Question 6 of 10
sergejj [24]
The answer is C.89,866. I multiplied 262x343.
3 0
2 years ago
A man holding a rock sits on a sled that is sliding across a frozen lake (negligible friction) with a speed of 0.480 m/s. The to
SpyIntel [72]
This is a problem of conservation of momentum

Momentum before throwing the rock: m*V = 96.0 kg * 0.480 m/s = 46.08 N*s

A) man throws the rock forward

=>

rock:
m1 = 0.310 kg
V1 = 14.5 m/s, in the same direction of the sled with the man

sled and man:
m2 = 96 kg - 0.310 kg = 95.69 kg
v2 = ?

Conservation of momentum:
momentum before throw = momentum after throw

46.08N*s = 0.310kg*14.5m/s + 95.69kg*v2

=> v2 = [46.08 N*s - 0.310*14.5N*s ] / 95.69 kg = 0.434 m/s

B) man throws the rock backward

this changes the sign of the velocity, v2 = -14.5 m/s

 46.08N*s = - 0.310kg*14.5m/s + 95.69kg*v2

v2 = [46.08 N*s + 0.310*14.5 N*s] / 95.69 k = 0.529 m/s


3 0
3 years ago
A circular cylinder has a diameter of 3.0 cm and a mass of 25 g. It floats in water with its long axis perpendicular to the wate
Vilka [71]

Answer:

   f = 5.3 Hz

Explanation:

To solve this problem, let's find the equation that describes the process, using Newton's second law

        ∑ F = ma

where the acceleration is

         a = \frac{d^2 y}{dt^2 }

        B- W = m \frac{d^2 y}{dt^2 }

To solve this problem we create a change in the reference system, we place the zero at the equilibrium point

           B = W

In this frame of reference, the variable y'  when it is oscillating is positive and negative, therefore Newton's equation remains

         B’= m \frac{d^2 y'}{dt^2 }

           

the thrust is given by the Archimedes relation

         B = ρ_liquid g V_liquid

     

the volume is

        V = π r² y'

     

we substitute

          - ρ_liquid g π r² y’ = m \frac{d^2 y'}{dt^2 }

          \frac{d^2 y'}{dt^2} + \rho_liquid \ g \ \pi  r^2/m ) y' \ =0

this differential equation has a solution of type

         y = A cos (wt + Ф)

where

         w² = ρ_liquid g π r² /m

angular velocity and frequency are related

         w = 2π f

         

we substitute

          4π² f² = ρ_liquid g π r² / m

          f = \frac{1}{2\pi } \ \sqrt{ \frac{ \rho_{liquid} \  \pi  r^2 \ g}{m } }

calculate

         f = \frac{1}{2 \pi }  \sqrt{ \frac{ 1000 \ \pi  \ 0.03^2 \ 9.8 }{0.025}  }

         f = 5.3 Hz

6 0
2 years ago
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