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UNO [17]
4 years ago
6

If the mass of the earth and all objects on it were suddenly doubled, but the size remained the same, the acceleration due to gr

avity at the surface would becomeA) 1/2 of what it now is.B) 2 times what it now is.C) 1/4 of what it now is.D) the same as it now is.E) 4 times what it now is.
Physics
1 answer:
Lerok [7]4 years ago
5 0

Answer:

B) 2 times what it now is

Explanation:

The acceleration due to gravity at the surface of the Earth is given by

g=\frac{GM}{R^2}

where

G is the gravitational constant

M is the mass of the Earth

R is the Earth's radius

In this problem, the mass of the Earth is doubled:

M' = 2M

while the radius remains the same:

R' = R

so the new acceleration due to gravity would be

g'=\frac{GM'}{R'^2}=\frac{G(2M)}{R^2}=2\frac{GM}{R^2}=2g

so, the acceleration due to gravity would become twice the current value.

Note also that the value of g does not depend on the mass of the objects involved.

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4 years ago
What is the mass of a school bus if it can accelerate from rest to 15.5 m/s over 8.25
alexandr1967 [171]

The mass of a school bus if it can accelerate from rest to 15.5 m/s over 8.25s with 7,500 N of force is 3989.4kg.

HOW TO CALCULATE MASS:

  • The mass of an object can be calculated by dividing the force applied to the object by its acceleration.

  • According to this question, a bus can accelerate from rest to 15.5 m/s over 8.25s. The acceleration can be calculated as follows:

  • a = (v - u)/t

  • a = 15.5 - 0/8.25

  • a = 15.5/8.25

  • a = 1.88m/s²

  • The mass of the bus = 7500N ÷ 1.88m/s²

  • The mass of the bus = 3989.4kg

  • Therefore, the mass of a school bus if it can accelerate from rest to 15.5 m/s over 8.25s with 7,500 N of force is 3989.4kg.

Learn more about mass at: brainly.com/question/20259048?referrer=searchResults

3 0
3 years ago
A rope attached to a load of 175 kg bricks Ilifts the bricks with a steady acceleration of 0.12.m/s^2 straight up. What is the t
andrew-mc [135]

Answer:

Tension, T = 1736 N

Explanation:

It is given that,

Mass of bricks, m = 175 kg

A rope is attached to a load of 175 kg bricks lifts the bricks with a steady acceleration of 0.12 m/s² in vertically upwards direction. let T is the tension in the rope. Using second equation of motion as :

T - mg = ma

T = ma + mg

T = m(a + g)

T = 175 kg ( 0.12 m/s² + 9.8 m/s² )

T = 1736 N

Hence, the tension in the wire is 1736 N.

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a. 1.2×10^-6

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c. 246.8×10^3

d. 88

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Answer:

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Explanation:

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