4.22 grams.
1. First find out how much AgNO3 weighs with one mole (107.87 g Ag + 14.007 g N + 48 g O = 169.89 grams)
2. Find the percent of Ag you have. So, (107.87 g/mol Ag)/(169.89 g/mol AgNO3)= 0.63 * 100 = 63%.
3. If you have 6.7 grams total, you know 63% of it is going to be silver, so just multiply 6.7 grams by .63 and you get 4.22 g Ag
Answer:
"0.053457 M" of sulfuric acid.
Explanation:
The given values are:
= 10 mL solution
= 12.20 mL
= 22.20 mL
then,
M 0.103 M of NaOH,
= experiment will not be affected
= 10.38 mL
Now,
⇒ mol of NAOH = MV
= 
= 
Whether Sulfuric acid, then
⇒ 
⇒ 
⇒ 
Before any dilution:

⇒ 

(Sulfuric acid)
I believe the statement above is true. <span>A </span>carbohydrate<span> is a </span>biological molecule<span> consisting of </span>carbon<span> (C), </span>hydrogen<span> (H) and </span>oxygen<span> (O) atoms, usually with a hydrogen–oxygen </span>atom ratio of 2:1. <span>When a </span>carbohydrate<span> is broken into its component sugar molecules by </span>hydrolysis<span> (e.g. sucrose being broken down into glucose and fructose), this is termed saccharification.</span>