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3 years ago

What is a crack in Earths crust along which eathquakes occur??

Chemistry

1 answer:

skelet666 [1.2K]3 years ago

8 0

The cracks are known as faults

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Write the formulae for the following and calculate the molecular mass for each one of them,

tatuchka [14]

Explanation:

a) NaHCO₃

= 23 + 1 + 12 + 16×3

= 23 + 1 + 12 + 48

= 84 g/mol

b) CaO

= 40 + 16

= 56 g/mol

c) NaCl

= 23 + 35.5

= 58.5 g/mol

8 0

3 years ago

Why is atp an example of chemical potential energy?

marta [7]

Hello! I hope this helps

Answer: ATP ( adenosine triphosphate) is considered as the energy currency of the cell as it stores energy in the cell. It is an example of chemical potential energy because energy is stored in the high energy containing phosphoanhydride bond (between phosphate molecules in the ATP).

7 0

3 years ago

A certain drug has a half-life in the body of 3.5h. Suppose a patient takes one 200.Mg pill at :500PM and another identical pill

tekilochka [14]

Answer:

The amount of drug left in his body at 7:00 pm is 315.7 mg.

Explanation:

First, we need to find the amount of drug in the body at 90 min by using the exponential decay equation:

$N_{t} = N_{0}e^{-\lambda t}$

Where:

λ: is the decay constant = $ln(2)/t_{1/2}$

$t_{1/2}$ : is the half-life of the drug = 3.5 h

N(t): is the quantity of the drug at time t

N₀: is the initial quantity

After 90 min and before he takes the other 200 mg pill, we have:

$N_{t} = 200e^{-\frac{ln(2)}{3.5 h}*90 min*\frac{1 h}{60 min}} = 148.6 mg$

Now, at 7:00 pm we have:

$t = 7:00 pm - (5:00 pm + 90 min) = 30 min$

$N_{t} = (200 + 148.6)e^{-\frac{ln(2)}{3.5 h}*30 min*\frac{1 h}{60 min}} = 315.7 mg$

Therefore, the amount of drug left in his body at 7:00 pm is 315.7 mg (from an initial amount of 400 mg).

I hope it helps you!

3 0

2 years ago

a 1.25g sample of ore containing iron pyrite (FeS2) was pulverized and ignited in air, converting the FeS2 to Fe2O3 and SO2(g).

svp [43]

Answer:

28.9%

Explanation:

Let's consider the following balanced equation.

2 FeS₂ + 11/2 O₂ ⇒ Fe₂O₃ + 4 SO₂

We can establish the following relations:

The molar mass of Fe₂O₃ is 159.6 g/mol
1 mole of Fe₂O₃ is produced per 2 moles of FeS₂
1 mole of Fe is in 1 mole of FeS₂
The molar mass of Fe is 55.84 g/mol

The amount of Fe in the sample that produced 0.516 g of Fe₂O₃ is:

$0.516gFe_{2}O_{3}.\frac{1molFe_{2}O_{3}}{159.6gFe_{2}O_{3}} .\frac{2molFeS_{2}}{1molFe_{2}O_{3}} .\frac{1molFe}{1molFeS_{2}} .\frac{55.84gFe}{1molFe} =0.361gFe$

The percent of Fe in 1.25 g of the ore is:

$\frac{0.361g}{1.25g} .100\%=28.9\%$

4 0

3 years ago

Need help ASAP!! What is a function mitochondrion

NISA [10]

Answer:

powerhouse of the cell

Explanation:

Mitochondria produce ATP, a necessary sugar that runs the cell

3 0

3 years ago