1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zhannawk [14.2K]
3 years ago
9

The rectangular plates in a parallel-plate capacitor are 0.063 m x 5.4 m. A distance of 3.5 x 10^-5m separate the plates. The pl

ates are separated by a dielectric made of Teflon , which has a dielectric constant of 2.1. What is the capacitance of the capacitor?
Physics
1 answer:
Aleks04 [339]3 years ago
5 0

The capacitance of the capacitor is 1.8\cdot 10^{-9}F

Explanation:

The capacitance of a parallel-plate capacitor is given by the equation

C=\frac{k\epsilon_0 A}{d}

where

k is the dielectric constant of the medium

\epsilon_0 = 8.85\cdot 10^{-12} F/m is the vacuum permittivity

A is the area of the plates

d is the separation between the plates

For the capacitor in this problem, we have:

k = 2.1 is the dielectric constant

d=3.5\cdot 10^{-5}m is the separation between the plates

A=0.063m \cdot 0.054m = 0.0034 m^2 (I assumed that 5.4 m is a typo, since it is not a realistic size for the side of the plate)

Therefore, the capacitance of the  capacitor is

C=\frac{(2.1)(8.85\cdot 10^{-12})(0.0034)}{3.5\cdot 10^{-5}}=1.8\cdot 10^{-9}F

Learn more about capacitors:

brainly.com/question/10427437

brainly.com/question/8892837

brainly.com/question/9617400

#LearnwithBrainly

You might be interested in
A 3.15-kg object is moving in a plane, with its x and y coordinates given by x = 6t2 − 4 and y = 5t3 + 6, where x and y are in m
ArbitrLikvidat [17]

Answer:

<h2>206.67N</h2>

Explanation:

The sum of force along both components x and y is expressed as;

\sum Fx = ma_x  \ and \ \sum Fy = ma_y

The magnitude of the net force which is also known as the resultant will be expressed as R =\sqrt{(\sum Fx)^2 + (\sum Fx )^2}

To get the resultant, we need to get the sum of the forces along each components. But first lets get the acceleration along the components first.

Given the position of the object along the x-component to be x = 6t² − 4;

a_x = \frac{d^2 x }{dt^2}

a_x = \frac{d}{dt}(\frac{dx}{dt} )\\ \\a_x = \frac{d}{dt}(6t^{2}-4  )\\\\a_x = \frac{d}{dt}(12t  )\\\\a_x = 12m/s^{2}

Similarly,

a_y = \frac{d}{dt}(\frac{dy}{dt} )\\ \\a_y = \frac{d}{dt}(5t^{3} +6 )\\\\a_y = \frac{d}{dt}(15t^{2}   )\\\\a_y = 30t\\a_y \ at \ t= 2.15s; a_y = 30(2.15)\\a_y = 64.5m/s^2

\sum F_x = 3.15 * 12 = 37.8N\\\sum F_y = 3.15 * 64.5 = 203.18N

R = \sqrt{37.8^2+203.18^2}\\ \\R = \sqrt{1428.84+41,282.11}\\ \\R = \sqrt{42.710.95}\\ \\R = 206.67N

Hence, the magnitude of the net force acting on this object at t = 2.15 s is approximately 206.67N

7 0
3 years ago
A 4.0 kg shot put is thrown with 30 N of force. What is its acceleration?
weeeeeb [17]

7.5 m/s

a = F ÷ m

a = (30 N) ÷ (4.0 kg)

a = 7.5 m/s2

7 0
3 years ago
Please help! I’ll give Brainliest
babymother [125]

Answer:

9.8 secs

Explanation:

the ball is in the air so it takes 9.8 secs to get to the ground

5 0
3 years ago
Read 2 more answers
Please help if you can.
VMariaS [17]

Initially there were 10 bulbs of 60 Watt power

So total power of all bulbs = 60 * 10 = 600 W

now each bulb used for 4 hours daily

so total energy consumed daily

E = P * t

E = 600 * 4 = 2400 Wh

E = 2.4 kWh

now we have total power consumed in 1 year

E = 365 * 2.4 = 876 kWh

cost of electricity = 10 cents/ kWh

so total cost of energy for one year

P_1 = 876 * 10 = 8760 cents = $87.60

Now if all 60 Watt bulbs are replaced by 30 Watt bulbs

So total power of all bulbs = 30 * 10 = 300 W

now each bulb used for 4 hours daily

so total energy consumed daily

E = P * t

E = 300 * 4 = 1200 Wh

E = 1.2 kWh

now we have total power consumed in 1 year

E = 365 * 1.2 = 438 kWh

cost of electricity = 10 cents/ kWh

so total cost of energy for one year

P_1 = 438 * 10 = 4380 cents = $43.80

total money saved in 1 year

Savings = 87.6 - 43.8 = $43.80

3 0
3 years ago
If you wanted to produce more power,what could you do to maximize power
PSYCHO15rus [73]

In physics, power is defined as energy per unit time.  You will also hear it described as work per unit time.  The standard unit of measure for power is the watt, where a watt is defined as joules (energy) per second (time).  This is expressed as a fraction as J/s.  If you wanted to increase the power in any operation, you can either increase the energy (more joules) or reduce the time (fewer seconds).

6 0
3 years ago
Read 2 more answers
Other questions:
  • A clam of mass 0.12 kg dropped by a seagull takes 3.0 s to hit the ground. [Neglect friction.]
    5·1 answer
  • Recently a local government has observed that the number of people suffering from respiratory diseases has increased. What measu
    6·2 answers
  • So we were working on some pulley problems but this one has kinda left me scratching my head, please help! My question is for pa
    10·1 answer
  • Which formula describes Boyle's law?
    5·1 answer
  • Assume the following vehicles are all moving at the Sam speed .it would be harder to change the velocity of which vehicle . What
    8·1 answer
  • A student applies a force of 245 N to move a bicycle 12.0 meters. How much work is done on the bicycle
    9·1 answer
  • A standard for comparison is called a frame of reference<br>True or False​​
    10·2 answers
  • If you are pushing a box toward your friend with a force of 20 N, and your friend is pushing the box toward you with a force of
    14·1 answer
  • A crane lifts 1800kg mass through a vertical height of 6cm in 9 seconds, Taking (g) as 10N/kg. what is the cranes power output?​
    14·1 answer
  • 5 waves with a length of 4m hit the shore every 2 seconds, what is the frequency?
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!