It doesn't matter. If the slides are truly frictionless, then
your kinetic energy at the bottom will be equal to the
potential energy you had at the top, no matter what kind
of route you took getting down.
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The only way I can think of that it would make a difference
would be if the shallow slide were REALLY REALLY long,
and you didn't have anything to eat all the way down.
Then you might lose some weight while you're on the slide,
and your mass might be less at the bottom than it was at the
top. Then, in order to have the same kinetic energy at the
bottom, you'd need to be going a little bit faster.
But if it takes less than, say, two or three days, to go down the
long, shallow slide, then this effect would probably be too small
to make any difference.
According to this photo, or i can recommend this video that helped me by tapton physics.
Answer:
The final position of the ship after the given time period is 42 km West of B.
Explanation:
Given;
average velocity of the ship, v = 35 km/h
time taken for the ship to reach point D, t = 1.2 hours
The position of the ship after the given time period is calculated as follows;
x = v x t
x = (35 km/h) x 1.2 h = 42 km
x = 42 km West of B.
Therefore, the final position of the ship after the given time period is 42 km West of B.
False, his first law states: An object that's in motion will remain in motion at a constant velocity unless it's acted on by an unbalanced force.
Answer:
2.465Ns;1.76N
Explanation:
From Newton's Second Law:
There is a conservation of Momentum hence:
Momentum before the impact equals that after the impact.
Hence.
1. The Impulse is same as the change in Momentum which is;
0.145 ×17 =2.465Ns { note: 145g in kg is 0.145}
2. From Newton's third Law; force is the rate of change of impulse expressed mathematically as;
F = m×v / t
Where m×v is impulse and t is time given.
F = 2.465/ 1.4 = 1.76N
