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4 years ago

Refraction occurs when a wave changes its A) color. B) frequency. C) intensity. D) speed.

Physics

2 answers:

mojhsa [17]4 years ago

4 0

Explanation :

Light shows many different types of phenomena like the reflection of light, refraction of light etc.

Refraction of light is the phenomena of bending of light when it passes from one medium to another. This is due to the difference in the refractive indices of two media.

Refractive index is given by :

$n=\dfrac{c}{v}$

c is the speed of light in vacuum

v is the speed of the light in a medium.

So, refraction occurs when a wave changes its speed.

Hence, the correct option is (D) "speed".

Gwar [14]4 years ago

3 0

The answer would be d. speed.

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Finish A 16 N force is applied to an object and 96 J of work is done. How far was the object moved?

Lina20 [59]

Answer:

$\boxed {\boxed {\sf 6 \ meters}}$

Explanation:

Work is the product of force and distance.

$W=F*d$

We know that 96 Joules of work were done and a 16 Newton force was applied to the object.

W= 96 J
F= 16 N

Substitute the values into the formula.

$96 \ J= 16 \ N * d$

First, let's convert the units. This will make cancelling units easier later in the problem. 1 Joule (J) is equal to 1 Newton meter (N*m), so the work of 96 Joules equals 96 Newton meters.

$96 \ N*m= 16 \ N * d$

Now, solve for distance by isolating the variable, d. It is being multiplied by 16 Newtons and the inverse of multiplication is division. Divide both sides of the equation by 16 N.

$\frac {96 \ N*m}{16 \ N}= \frac{16 \ N *d}{16 \ N}$

$\frac {96 \ N*m}{16 \ N}=d$

The units of Newtons cancel.

$\frac {96}{16} \ m = d$

$6 \ m = d$

The object moved a distance of 6 meters.

3 0

3 years ago

Help me please! i will give brainliest i need it done i know its easy but i have a lot of work to do

cricket20 [7]

Answer:

Down below :)

Explanation:

1. Solid - A

2. Liquid - C

3. Gas - E

4. Melting - G

5. Evaporation - F

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2 years ago

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What are the characteristics of high energy waves?

Temka [501]

Amplitude and frequency

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3 years ago

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A piano emits frequencies the range from a low of about 28 Hz to a high of about 4200 Hz. Find the range of wavelengths in air a

Step2247 [10]

V=wave velocity , f= frequency, λ=wavelength 
Use it to find corresponding wavelengths for f=28 Hz 
λ= v/f= 337/28=12.036 m

for f=4200 Hz 
λ= v/f=337/4200= 0.08 m 
So max. wavelength is 12.036 m and 
Min Wavelength is 0.08 m 
So the range is between .08 m and 12.036 m
Hope this helps.

4 0

4 years ago

A powerful searchlight shines on a man. The man's cross-sectional area is 0.500m2 perpendicular to the light beam, and the inten

babymother [125]

Answer:

The magnitude of the force the light beam exerts on the man is 5.9 x 10⁻⁵N

(b) the force the light beam exerts is much too small to be felt by the man.

Explanation:

Given;

cross-sectional area of the man, A = 0.500m²

intensity of light, I = 35.5kW/m²

If all the incident light were absorbed, the pressure of the incident light on the man can be calculated as follows;

P = I/c

where;

P is the pressure of the incident light

I is the intensity of the incident light

c is the speed of light

$P = \frac{I}{c} =\frac{35500}{3*10^8} = 1.18*10^{-4} \ N/m^2$

F = PA

where;

F is the force of the incident light on the man

P is the pressure of the incident light on the man

A is the cross-sectional area of the man

F = 1.18 x 10⁻⁴ x 0.5 = 5.9 x 10⁻⁵ N

The magnitude of the force the light beam exerts on the man is 5.9 x 10⁻⁵ N

Therefore, the force the light beam exerts is much too small to be felt by the man.

8 0

4 years ago