Answer:
The diameter of the shaft is 80.5 mm.
Explanation:
Torsion equation is applied for the diameter of the solid shaft.
Step1
Given:
Power of the shaft is 100 kw.
Revolution per minute is 160 RPM.
Allowable shear stress is 70 Mpa.
Maximum torque is 20% more than the mean torque.
Step2
Mean torque is calculated as follows:



T=5968.31 N-m
Step3
Maximum torque is calculated as follows:



T_{max}=7161.97 N-m
Step4
Apply torsional equation for diameter of shaft as follows:



d=0.0805 m
or,
d=80.5 mm
Thus, the diameter of the shaft is 80.5 mm.
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Answer:
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Answer:
Employers must comply with OSHA's regulations to safeguard workers from caught-in or -between dangers, which include, but are not limited to, the following:
• Protect power tools and other equipment with moving parts with guards.
• Support, secure, or otherwise make safe any equipment that has pieces that workers could become entangled in.
· Take precautions to avoid workers being crushed by tipped-over heavy machinery.
• Take precautions to avoid pinning workers between equipment and a solid object.
• Provide workers with protection when trenching and excavating.
• Provide ways to prevent constructions, such as scaffolds, from collapsing.
Explanation: