1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Doss [256]
3 years ago
11

A saturated 1.5 ft3 clay sample has a natural water content of 25%, shrinkage limit (SL) of 12% and a specific gravity (GS) of 2

.70. Determine the volume of the sample when the water content is 10%.

Engineering
1 answer:
Svetllana [295]3 years ago
7 0

79 f t^{3} is the volume of the sample when the water content is 10%.

<u>Explanation:</u>

Given Data:

V_{1}=100\ \mathrm{ft}^{3}

First has a natural water content of 25% = \frac{25}{100} = 0.25

Shrinkage limit, w_{1}=12 \%=\frac{12}{100}=0.12

G_{s}=2.70

We need to determine the volume of the sample when the water content is 10% (0.10). As we know,

V \propto[1+e]

\frac{V_{2}}{V_{1}}=\frac{1+e_{2}}{1+e_{1}}  ------> eq 1

e_{1}=\frac{w_{1} \times G_{s}}{S_{r}}

The above equation is at S_{r}=1,

e_{1}=w_{1} \times G_{s}

Applying the given values, we get

e_{1}=0.25 \times 2.70=0.675

Shrinkage limit is lowest water content

e_{2}=w_{2} \times G_{s}

Applying the given values, we get

e_{2}=0.12 \times 2.70=0.324

Applying the found values in eq 1, we get

\frac{V_{2}}{100}=\frac{1+0.324}{1+0.675}=\frac{1.324}{1.675}=0.7904

V_{2}=0.7904 \times 100=79\ \mathrm{ft}^{3}

You might be interested in
NO reacts with Br2 in the gas phase according to the following chemical equation: 2NO(g) +Br2(g)2NOBr(g) It is observed that, wh
klemol [59]

Answer:

a) rate=r=k[NO]^{2} [Br_{2}]^{1}

b) k=\frac{1}{s*M^{2}}

Explanation:

First of all you need to indicate the reaction order of each reactant ( NO and Br_{2}):

1.  Br_{2}

Note that if Br_{2} concentration ([Br_{2} ]) is reduced to 1/3 of its initial value, the rate of the reaction is also reduced to 1/3 of its initial value, it means:

[Br_{2} ]=1/3 then r=1/3

As the change in the rate of the reaction is equal to the change of the initial concentration of  Br_{2}, you could concluded that the reaction is first order with respect to  Br_{2}

2. NO

Now, note that if NO concentration ([NO]) is multiplied by 3.69, the rate of the reaction increases by a factor of 13.6. In this case, to know the ratio could be advisable divide the rate of the reaction (13.6) over the factor whereby was multiplied the concentration (3.69), as follows:

\frac{13.6}{3.69}=3.69

As the result is the same factor 3.69 you could concluded that the change of the rate of reaction is proportional to the square of the concentration of A:

r=[NO]^{2} =3.68^{2} =13.6

It means that the reaction is second order with respect to NO

3. Rate Expression

Remember that the rate expression of the reactions depend on the concentration of each reactant and its order. In this case we have 2 reactants: NO and Br_{2}, then we have a rate law depending of  2 concentrations, as follows:

<h2>rate=r=k[NO]^{2} [Br_{2}]^{1}</h2>

Note that the expression is the result of the concentration of each reactant raised to its reaction order (previously determined)

<em>Note: I hope that you do not mix up the use of the rates of reaction of each reactant, that is experimentally determined, with the stoichiometric coefficient, are different.</em>

4. Rate constant units (k)

Assuming concentration is expressed as \frac{mol}{L}=M and time is in second, to find the units of k we need to solve an equation with units and with supporting of the rate equation previously obtained, as follows:

r=k[NO]^{2} [Br_{2}]^{1}

Where:

[r]=[\frac{M}{s}]

[[NO]]=[M]

[ [Br_{2}]]=[M]

Then:

\frac{M}{s}=kM^{2} M^{1}

\frac{M}{s}=kM^{3}

\frac{M}{s*M^{3}}=k

The units of the rate constant k are:

k=\frac{1}{s*M^{2}}

8 0
3 years ago
Find the equivalent impedance Zeq seen by the source when Vs = 2 cos (5t) v, C = 0.2 F, R = 1 Ω and L = 0.1 H. (Give angles in d
Yanka [14]

Answer:

0.89 cos (st +116.57°v)

Explanation:

Please kindly check attachment for the step by step solution of the given problem.

6 0
3 years ago
ceramics must be heated in order to harden the clay and make it durable. the equipment used to heat the clay
SIZIF [17.4K]

Ceramics must be heated in order to harden the clay and make it durable. The tool used to heat the clay is called a Kiln.

<h3>What happens when ceramic is heated?</h3>

Cristobalite is a silica polymorph that is used in ceramics. Quartz particles in porcelain can change into cristobalite during burning. This has effects on the fired matrix's thermal expansion. When there is a high level of vitrification or a shape is unstable during the firing of ceramic ware, warping occurs.

Ceramic items are porous, brittle, and rigid. They are thus employed in the production of glass, ceramics, cement, and bricks. Additionally, ceramics are employed extensively in gas turbine engines. Artificial bones and dental implants are both made of bio-ceramics.

Any of the several tough, fragile, heat- and corrosion-resistant materials created by sculpting and then heating an inorganic, nonmetallic material like clay to a high temperature are known as ceramics.

In order to solidify the clay and make ceramics durable, heat must be applied. A kiln is the name of the device used to heat clay.

To learn more about ceramics refer to:

brainly.com/question/26247382

#SPJ4

5 0
2 years ago
Water flows through a horizontal plastic pipe with a diameter of 0.15 m at a velocity of 15 cm/s. Determine the pressure drop pe
Sonja [21]

Answer:0.1898 Pa/m

Explanation:

Given data

Diameter of Pipe\left ( D\right )=0.15m

Velocity of water in pipe\left ( V\right )=15cm/s

We know viscosity of water is\left (\mu\right )=8.90\times10^{-4}pa-s

Pressure drop is given by hagen poiseuille equation

\Delta P=\frac{128\mu \L Q}{\pi D^4}

We have asked pressure Drop per unit length i.e.

\frac{\Delta P}{L} =\frac{128\mu \ Q}{\pi D^4}

Substituting Values

\frac{\Delta P}{L}=\frac{128\times8.90\times10^{-4}\times\pi \times\left ( 0.15^{3}\right )}{\pi\times 4 \times\left ( 0.15^{2}\right )}

\frac{\Delta P}{L}=0.1898 Pa/m

4 0
3 years ago
A spacecraft is fueled using hydrazine ​(N2H4​; molecular weight of 32 grams per mole​ [g/mol]) and carries 1 comma 630 kilogram
Varvara68 [4.7K]

Answer:

attached below

Explanation:

7 0
3 years ago
Other questions:
  • The enthalpy of the water entering an actual pump is 500 kJ/kg and the enthalpy of the water leaving it is 550 kJ/kg. The pump h
    10·1 answer
  • For problems 1 and 2, six luminaires, similar to Style E used in the Commercial Building, are to be installed in a room that is
    13·1 answer
  • Block A is released from rest and slides down the frictionless ramp to the loop. The maximum height h of the loop is the same as
    6·1 answer
  • When wasDisney Cruise Line founded
    5·1 answer
  • 9.21 A household oven door of 0.5-m height and 0.7-m width reaches an average surface temperature of 32℃ during operation. Estim
    8·1 answer
  • What is the thermal efficiency of this reheat cycle in terms of enthalpies?
    11·1 answer
  • Air, at a free-stream temperature of 27.0°C and a pressure of 1.00 atm, flows over the top surface of a flat plate in parallel f
    13·1 answer
  • Three consequences of unbalanced wheels on a motor vehicle​
    11·1 answer
  • What building codes did Mega Corporation fail to follow?
    9·1 answer
  • You may wonder who the rest goes
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!