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3 years ago

Dimensional analysis a gas station is charging $12.99 per gallon of gas what would be the price for a liter of gas

Chemistry

1 answer:

Snowcat [4.5K]3 years ago

5 0

So you would do 12.99 / 4 which = about 3.25 per liter of gas

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A solution is prepared by condensing 4.00 L of a gas,

vredina [299]

Answer:

-2.3 ºC

Explanation:

Kf (benzene) = 5.12 ° C kg mol – 1

1st - We calculate the moles of condensed gas using the ideal gas equation:

n = PV / (RT)

P = 748/760 = 0.984 atm

T = 270 + 273.15 = 543.15 K

V = 4 L

R = 0.082 atm.L / mol.K

n = (0.984atm * 4L) / (0.082atm.L / K.mol * 543.15K) = 0.088 mol

Then, you calculate the molality of the solution:

m = n / kg solvent

m = 0.088 mol / 0.058 kg = 1.52mol / kg

Then you calculate the decrease in freezing point (DT)

DT = m * Kf

DT = 1.52 * 5.12 = 7.8 ° C

Knowing that the freezing point of pure benzene is 5.5 ºC, we calculate the freezing point of the solution:

T = 5.5 - 7.8 = -2.3 ºC

5 0

3 years ago

Which action is a change in state

Mariana [72]

Answer: condensing

Explanation:

8 0

2 years ago

Consider an oxygen-concentration cell consisting of two zinc electrodes. One is immersed in a water solution with a low oxygen c

blsea [12.9K]

Answer:

(a) The anode electrode which comprises the zinc electrode being placed in a water solution with low oxygen concentration.

(b) Cathodic reaction is: $O_{2} + 2H_{2}O + 4e^{-}$ ⇒ $4OH^{-}$

Anodic reaction is: $Zn$ ⇒ $Zn^{2+} + 2e^{-}$

Explanation:

In the given problem, we have an oxygen-concentration cell consisting of two zinc electrodes. One is immersed in a water solution with a low oxygen concentration and the other in a water solution with a high oxygen concentration. The zinc electrodes are connected by an external copper wire.

(a) Which electrode will corrode?

The electrode that will corrode is the anode electrode which comprises the zinc electrode being placed in a water solution with low oxygen concentration.

(b) Write half-cell reactions for the anodic reaction and the cathodic reaction.

Cathodic reaction is: $O_{2} + 2H_{2}O + 4e^{-}$ ⇒ $4OH^{-}$

Anodic reaction is: $Zn$ ⇒ $Zn^{2+} + 2e^{-}$

6 0

3 years ago

How far in advance is weather forecasting most accurate

Vesnalui [34]

I'm like 99% sure its one week

8 0

3 years ago

Read 2 more answers

An unknown solution has a pH of 2. How would you classify this solution?

devlian [24]

Acidic because anything over a ph of 7 would be basic but anything below 7 would be acid and if it has a ph of 7 it would be neutral....Hope I helped

7 0

3 years ago