4. What is the pressure (in atm) of a gas trapped in a balloon along with water vapor at

The work done depends upon the --------------applied and the -------------- produced

Deffense [45]

Answer:

The work done depends upon the Force applied and Displacement produced.

Explanation:

Definition: Work is said to be on a body only if a force acting on it causes a displacement in its direction .

In other words we can say it is the product of force and displacement

Formula:

$Work = Force\times Displacement\ cos \theta$

Unit:

The unit of work is Joule.

So, work depends on the force applied and the displacement caused by the applied force.

If force is applied and there is no displacement, then work is 0 .

Example: Pushing a wall does no work.

Work is positive if force applied and displacement is in same direction.

Work is negative if force applied and displacement is in opposite direction.

3 0

3 years ago

In order to complete his research project, Roger needs to make a mixture of 86 mL of a 36% acid solution from a 39% acid

Zina [86]

The volume of the 39% acid solution that Roger needs to use to make a mixture of 86 mL of a 36% acid solution is 74.27 mL.

The mixture of the acids solutions is given by:

$CV = C_{1}V_{1} + C_{2}V_{2}$ (1)

Where:

C: is the concentration if the mixture = 36%

V: is the total volume of the mixture = 86 mL

C₁: is the concentration of acid 1 = 39%

V₁: is the volume if acid 1 =?

C₂: is the concentration of acid 2 = 17%

V₂: is the volume of acid 2

The sum of V₁ and V₂ must be equal to V, so:

$V = V_{1} + V_{2}$

$V_{2} = V - V_{1}$ (2)

By entering equation (2) into (1), we have:

$CV = C_{1}V_{1} + C_{2}(V - V_{1})$

$36\%*86 mL = 39\%*V_{1} + 17\%(86 mL - V_{1})$

Changing the percent values to decimal ones:

$0.36*86 mL = 0.39*V_{1} + 0.17(86 mL - V_{1})$

Now, by solving the above equation for V₁:

$V_{1} = 74.27 mL$

Therefore, the volume of the 39% acid solution is 74.27 mL.

To learn more about mixture and solutions, go here: brainly.com/question/6358654?referrer=searchResults

I hope it helps you!

7 0

2 years ago

Read 2 more answers

An impure sample of table salt that weighed 0.8421 g, when dissolved in water and treated with excess AgNO3, formed 2.044 g of A

Lilit [14]

Answer:

99.24%.

Explanation:

NaCl reacted with AgNO₃ as in the balanced equation:

NaCl + AgNO₃ → AgCl(↓) + NaNO₃,

1.0 mol of NaCl reacts with 1.0 mol of AgNO₃ to produce 1.0 mol of AgCl and 1.0 mol of NaNO₃.

We need to calculate the no. of moles of AgCl produced:

no. of moles of AgCl = mass/molar mass = (2.044 g)/(143.32 g/mol) = 0.0143 mol.

Now, we can calculate the no. of moles of NaCl that can precipitated as AgCl (0.0143 mol), these moles represents the no. of moles of pure NaCl in the sample:

using cross multiplication:

1.0 mol of NaCl produce → 1.0 mol of AgCl, from the stichiometry.

∴ 0.0143 mol of NaCl produce → 0.0143 mol of AgCl.

Now, we can get the mass of puree NaCl in the sample:

mass of pure NaCl = (no. of moles of pure NaCl)(molar mass of NaCl) = (0.0143 mol)(58.44 g/mol) = 0.8357 g.

∴ The percentage of NaCl in the impure sample = [(mass of pure NaCl)/(mass of the impure sample)] x 100 = [(0.8357 g)/(0.8421 g)] x 100 = 99.24%.

4 0

3 years ago

What's the balanced chemical equation of magnesium reacting with silver nitrate to produce silver and magnesium nitrate?

Strike441 [17]

The balanced equation is Mg + 2AgNO₃ ⟶ Mg(NO₃)₂ + 2Ag

Step 1. Write the unbalanced equation

Mg + AgNO₃ ⟶ Mg(NO₃)₂ + Ag

Step 2. Start with the most complicated-looking formula [Mg(NO₃)₂] and balance its atoms.

Mg: Already balanced —1 atom each side.

N: We need 2 N on the left. Put a 2 in front of AgNO₃.

1Mg + 2AgNO₃ ⟶ 1Mg(NO₃)₂ + Ag

O: Already balanced —6 atom6 each side.

Step 3: Balance Ag

We have 2Ag on the left. We need 2Ag on the right.

1Mg + 2AgNO₃ ⟶ 1Mg(NO₃)₂ + 2Ag

4 0

3 years ago

A hiker seals a plastic bag that contains dried fruit before the climbs a mountain. What will most likely happen to the plastic

romanna [79]

From the ideal gas equation,

$PV = nRT$

where n is number of moles, R is Universal gas constant, P is pressure, V is volume, and T is temperature of the gas.

The pressure and volume are inversely proportional to each other at constant temperature and number of moles.

Hence, on decreasing the pressure, the volume will increase.

As the hiker reaches a height of a mountain, the pressure would decrease which results in the reestablishment of equilibrium between gas molecules thus resulting in pushing of bag outwards.

Hence, the bag will expand as the hiker reaches the top of the mountain.

5 0

2 years ago