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aleksandrvk [35]
2 years ago
7

What type of chemical reaction is Ba(ClO3)2 --> BaCl2 + O2.

Chemistry
1 answer:
puteri [66]2 years ago
3 0

(Ba(ClO_3)_2)  → BaCl_2 + O_2 is a decomposition reaction. Barium chlorate (Ba(ClO_3)_2) decomposes to give barium chloride and oxygen.

<h3>What is decomposition reaction?</h3>

A decomposition reaction can be defined as a chemical reaction in which one reactant breaks down into two or more products.

A decomposition reaction produces multiple products from a single reactant.

Combustion reactions are the combination of some compound with oxygen to make oxides of the other elements as products.

Hence, (Ba(ClO_3)_2)  → BaCl_2 + O_2 is a decomposition reaction. Barium chlorate (Ba(ClO_3)_2) decomposes to give barium chloride and oxygen.

Learn more about the decomposition reaction here:

brainly.com/question/8009068

#SPJ1

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kotykmax [81]

Answer: Mg is the excess reactant for the forward reaction.

Explanation: It is a stoichiometry problem and solved with the help of given grams and using balanced equation. Grams of both the reactants are converted to moles and divided by their coefficients. The excess reactant is the one for which we get the highest number on doing above steps.

The balanced equation is:

SiCl_4(l)+2Mg(s)\rightarrow 2MgCl_2(s)+Si(s)

Molar mass of silicon tetra chloride is 169.9 gram per mol and the molar mass of Mg is 24.3 gram per mol.

53.8gSiCl_4(\frac{1mol}{169.9g})

= 0.317molSiCl_4

65.0gMg(\frac{1mol}{24.3g})

= 2.67 mol Mg

From balanced equation, the coefficient of silicon tetra chloride is 1 and that of Mg is 2. So, we will divide the moles of silicon tetra chloride by 1 and that of Mg by 2 and see which one gives highest number.

For silicon tetra chloride, \frac{0.317}{1}  = 0.317

and for Mg, \frac{2.67}{2}  = 1.34

The highest number is for Mg and so the excess reactant for the forward reaction is Mg.

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How many moles of helium are needed to fill a balloon to a volume of 5.3 L at 22 ℃ and 632 mmHg?
son4ous [18]

Answer:

0.18 moles

Explanation:

Applying,

PV = nRT................... Equation 1

Where P = pressure, V = volume, n = number of moles, R = molar gas constant, T = temperature.

make n the subject of the equation

n = PV/RT............... Equation 2

Given: V = 5.3 L, T = 22 °C = (22+272) K = 295 K, P = 632 mmHg = (0.00131579×632) = 0.8316 atm,  R = 0.083 L.atm/K.mol

Substitute these values into equation 2

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