1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Llana [10]
3 years ago
13

Which of these items best describes the arrangement of electrons in an atom of sulfur? A. Eight electrons in its first energy le

vel; eight valence electrons in its outermost shell B. Two electrons in its first energy level; two electrons in its second energy level; eight electrons in its third energy level; four valence electrons in its outermost energy level C. Two valence electrons in its first energy level; eight electrons in its second energy level; six electrons in its outermost energy level D. Two electrons in its first energy level; eight electrons in its second energy level; six valence electrons in its outermost energy level
Chemistry
2 answers:
Serga [27]3 years ago
6 0

D. Two electrons in its first energy level; eight electrons in its second energy level; six valence electrons in its outermost energy level.

Please correct me if I'm wrong!! :)


Ivenika [448]3 years ago
6 0

<u>Answer:</u> The correct answer is Option D.

<u>Explanation:</u>

Valence electrons are defined as the electrons which are present in the outermost shell of an atom. Outermost shell has the highest value of 'n' that is principal quantum number.

Sulfur is the 16th element of the periodic table having 16 electrons. The electronic configuration of this element is: 1s^22s^22p^63s^23p^4

The number of electrons in first shell (n = 1) : 2

The number of electrons in second shell (n = 2) : (2 + 6) = 8

The number of electrons in third shell, outermost shell (n = 3) : (2 + 4) = 6

The number of valence electrons in sulfur atom are 6

Hence, the correct answer is Option D.

You might be interested in
A voltaic cell consists of a Zn&gt;Zn2+ half-cell and a Ni&gt;Ni2+ half-cell at 25 °C. The initial concentrations of Ni2+ and Zn
nlexa [21]

Answer :

(a) The initial cell potential is, 0.53 V

(b) The cell potential when the concentration of Ni^{2+} has fallen to 0.500 M is, 0.52 V

(c) The concentrations of Ni^{2+} and Zn^{2+} when the cell potential falls to 0.45 V are, 0.01 M and 1.59 M

Explanation :

The values of standard reduction electrode potential of the cell are:

E^0_{[Ni^{2+}/Ni]}=-0.23V

E^0_{[Zn^{2+}/Zn]}=-0.76V

From this we conclude that, the zinc (Zn) undergoes oxidation by loss of electrons and thus act as anode. Nickel (Ni) undergoes reduction by gain of electrons and thus act as cathode.

The half reaction will be:

Reaction at anode (oxidation) : Zn\rightarrow Zn^{2+}+2e^-     E^0_{[Zn^{2+}/Zn]}=-0.76V

Reaction at cathode (reduction) : Ni^{2+}+2e^-\rightarrow Ni     E^0_{[Ni^{2+}/Ni]}=-0.23V

The balanced cell reaction will be,  

Zn(s)+Ni^{2+}(aq)\rightarrow Zn^{2+}(aq)+Ni(s)

First we have to calculate the standard electrode potential of the cell.

E^o=E^o_{cathode}-E^o_{anode}

E^o=E^o_{[Ni^{2+}/Ni]}-E^o_{[Zn^{2+}/Zn]}

E^o=(-0.23V)-(-0.76V)=0.53V

(a) Now we have to calculate the cell potential.

Using Nernest equation :

E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Zn^{2+}]}{[Ni^{2+}]}

where,

n = number of electrons in oxidation-reduction reaction = 2

E_{cell} = emf of the cell = ?

Now put all the given values in the above equation, we get:

E_{cell}=0.53-\frac{0.0592}{2}\log \frac{(0.100)}{(1.50)}

E_{cell}=0.49V

(b) Now we have to calculate the cell potential when the concentration of Ni^{2+} has fallen to 0.500 M.

New concentration of Ni^{2+} = 1.50 - x = 0.500

x = 1 M

New concentration of Zn^{2+} = 0.100 + x = 0.100 + 1 = 1.1 M

Using Nernest equation :

E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Zn^{2+}]}{[Ni^{2+}]}

Now put all the given values in the above equation, we get:

E_{cell}=0.53-\frac{0.0592}{2}\log \frac{(1.1)}{(0.500)}

E_{cell}=0.52V

(c) Now we have to calculate the concentrations of Ni^{2+} and Zn^{2+} when the cell potential falls to 0.45 V.

Using Nernest equation :

E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Zn^{2+}+x]}{[Ni^{2+}-x]}

Now put all the given values in the above equation, we get:

0.45=0.53-\frac{0.0592}{2}\log \frac{(0.100+x)}{(1.50-x)}

x=1.49M

The concentration of Ni^{2+} = 1.50 - x = 1.50 - 1.49 = 0.01 M

The concentration of Zn^{2+} = 0.100 + x = 0.100 + 1.49 = 1.59 M

5 0
3 years ago
What is the name of the hydrocarbon CH3(CH2)6CH3?
Brums [2.3K]

Answer is: n-octane.

Octane is the straight-chain alkane (an acyclic saturated hydrocarbon) with eight carbon atoms.

Carbons in octane have sp3 hybridization (carbon’s 2s and three 2p orbitals combine into four identical sp3 orbitals).

Orbitals in sp3 hybridization have a tetrahedral arrangement and form single (sigma) bonds.

Burning octane fuel is very fast chemical reaction, it happens in immediately.

Main products of the combustion of fossil fuels are carbon(IV) oxide and water.  

Chemical reaction: C₈H₁₈ + 25/2O₂ → 8CO₂ + 9H₂O; ΔH = -5500 kJ/mol.


5 0
3 years ago
Read 2 more answers
Cells that carry info throughout your nervous system
Rama09 [41]

Neurons are cells that carry info in the nervous system

8 0
3 years ago
The work function for metallic magnesium is 3.68 eV. Calculate the velocity in km/s for electrons ejected from a metallic magnes
Lemur [1.5K]

Answer:

v = 301.62 km/s

Explanation:

Given that:

The work function of the magnesium = 3.68 eV

Energy in eV can be converted to energy in J as:

1 eV = 1.6022 × 10⁻¹⁹ J

So, work function = 3.68\times 1.6022\times 10^{-19}\ J=5.8961\times 10^{-19}\ J

Using the equation for photoelectric effect as:

E=\psi _0+\frac {1}{2}\times m\times v^2

Also, E=\frac {h\times c}{\lambda}

Applying the equation as:

\frac {h\times c}{\lambda}=\psi _0+\frac {1}{2}\times m\times v^2

Where,  

h is Plank's constant having value 6.626\times 10^{-34}\ Js

c is the speed of light having value 3\times 10^8\ m/s

m is the mass of electron having value 9.11\times 10^{-31}\ kg

\lambda is the wavelength of the light being bombarded

\psi _0=Work\ function

v is the velocity of electron

Given, \lambda=315\ nm=315\times 10^{-9}\ m

Thus, applying values as:

\frac{6.626\times 10^{-34}\times 3\times 10^8}{315\times 10^{-9}}=5.8961\times 10^{-19}+\frac{1}{2}\times 9.11\times 10^{-31}\times v^2

5.8961\times \:10^{-19}+\frac{1}{2}\times \:9.11\times \:10^{-31}v^2=\frac{6.626\times \:10^{-34}\times \:3\times \:10^8}{315\times \:10^{-9}}

\frac{1}{2}\times 9.11\times 10^{-31}\times v^2=6.31047619\times 10^{-19}-5.8961\times 10^{-19}

\frac{1}{2}\times 9.11\times 10^{-31}\times v^2=0.41437619\times 10^{-19}

v^2=0.0909717212\times 10^{12}

v = 3.0162 × 10⁵ m/s

Also, 1 m = 0.001 km

So, v = 301.62 km/s

8 0
3 years ago
after searching for artificial sweeteners, do you think it is appropriate to have diet pop available in your school?
AnnZ [28]
Artificial sweeteners are often the topic of heated debate. On one hand, they're claimed to increase your risk of cancer and harm your blood sugar and gut health. On the other hand, most health authorities consider them safe, and many people use them to reduce their sugar intake and lose weight. To wrap this up, diet pop should not.
4 0
3 years ago
Other questions:
  • What represents the point where water vapor condenses back to liquid?
    10·2 answers
  • What two gases make up 99% of the Earth's atmosphere? A. Nitrogen and water vapor B. Carbon dioxide and oxygen C. Carbon dioxide
    13·1 answer
  • Which nuclear emission is negatively charged?
    13·2 answers
  • What does it mean if something is insoluble
    7·1 answer
  • Which is an example of a base?a(lemon juice b(baking soda c(an insolator d( water
    9·1 answer
  • 11. A student is studying guppies, a type of fish. The student learns
    6·1 answer
  • Write a balenced chemical equation for the reaction: include abbreviation for the physical states-
    5·1 answer
  • Ask BRIA
    7·1 answer
  • Which best describes species C?
    11·2 answers
  • What is the value of c?<br> 56.70
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!