Answer:
A. Kate’s location is at a lower latitude.
C. Kate’s location absorbs sunlight that travels a shorter distance through the atmosphere.
Explanation:
^
OK. So you're pushing on the small box, and on the other side of it, the small
box is pushing on the big box. So you're actually pushing both of them.
-- The total mass that you're pushing is (5.2 + 7.4) = 12.6 kg.
-- You're pushing it with 5.0N of force.
-- Acceleration of the whole thing = (force)/(mass) = 5/12.6 = <em>0.397 m/s²</em> (rounded)
-- Both boxes accelerate at the same rate. So the box farther away from you ...
the big one, with 7.4 kg of mass, accelerates at the same rate.
The force on it to make it accelerate is (mass) x (acceleration) =
(7.4 kg) x (5/12.6 m/s²) = <em>2.936 N.</em>
The only force on the big box comes from the small box, pushing it from behind.
So that same <em>2.936N</em> must be the contact force between the boxes.
The answer is D, Carbon and hydrogen
Answer:
north direction.
Explanation:
The wire carries a current towards the east . The magnetic field will make circular path around the wire in clockwise direction so at a point just south of wire , magnetic field will be into the plane of paper containing wire. If we take east as x -axes , north as y axes then out of plane will form z axes. Hence direction of magnetic field will be - z direction .
Magnetic field can be represented as - B k
Proton is moving towards east ie in + x direction so it can be represented as follows
velocity = V i
Force F = q( V i x -B k)
= ( BqV) j or + ve j direction or along north direction
So direction of force will be along north direction.
Answer:
The magnitude of the acceleration of a proton at a distance of 1.5cm from the bead is 5.6 x10^13m/s².
The magnitude of the acceleration of a proton at a distance of 1.5cm from the bead is 9.8 x10^16m/s².
Explanation:
Newton's second law states that the total sum of the force acting on a particle in motion is equal to the mass of the particle times the acceleration due to the force. So the electric force between the bead and proton is equal to ma. That is,
Fe = kq1*q2/r² = m*a
The proton had a charge of +1.6x10^-19C and a mass of 1.67×10^-27kg
By substituting these values into the equivalent for a we have that the acceleration of the proton at a distance of 1.5cm form the bead is 5.6×10^13m/s²
The proton had a charge of -1.6x10^-19C and a mass of 9.10×10^-31kg
By substituting these values into the equivalent for a we have that the acceleration of the proton at a distance of 1.5cm form the bead is 9.8×10^16m/s²