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AURORKA [14]
3 years ago
5

A long, straight, horizontal wire carries current toward the east. A proton moves toward the east alongside and just south of th

e wire. What is the direction of the magnetic force on the proton?
Physics
1 answer:
kondor19780726 [428]3 years ago
4 0

Answer:

north direction.

Explanation:

The wire carries a current towards the east . The magnetic field will make circular path around the wire in clockwise direction  so at a point just south of wire , magnetic field will be into the plane of paper containing wire. If we take east as x -axes , north as y axes then out of plane will form z axes. Hence direction of magnetic field will be -  z direction .

Magnetic field can be represented as - B k

Proton is moving towards east ie in + x direction so it can be represented as follows

velocity = V i

Force F = q( V i x -B k)

= ( BqV) j or + ve j direction or along north direction

So direction of force will be along north direction.

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Tectonic plates are large segments of the Earth's crust that move slowly. Suppose that one such plate has an average speed of 4.
Kay [80]

Answer:

a) 1.268×10⁻⁷ cm/sec

b) 40 km/million years.

Explanation:

Speed of tectonic plate = 4.0 cm/year

a) Convert the year to seconds

1 year = 365 days × 24 hours × 60 minutes × 60 seconds

⇒1 year = 31536000 seconds

So,

4\ cm/year = \frac{4}{31536000}\\\Rightarrow 4\ cm/year = \frac{1}{7884000}\\\Rightarrow 4\ cm/year = 1.268\times 10^{-7} cm/sec

Distance plate will move in 1 second is 1.268×10⁻⁷ cm/sec

b) Convert cm to km

4\ cm=\frac{4}{10^{-5}}\ km

So, in 1 year it will move 0.00004 km

Hence in 1 million years is will move

0.00004 × 10⁶ = 40 km/million years.

Speed in kilometers per million years is 40 km/million years.

3 0
3 years ago
Two wheels roll side-by-side without sliding, at the same speed. The radius of wheel 2 is one-half (1/2) the radius of wheel 1.
Lemur [1.5K]

Answer:

w'=(1/2)w

Explanation:

In order to calculate the angular velocity of the second wheel, you use the following formula:

\omega=\frac{v}{r}      (1)

v: speed of the wheel 1 = speed of the wheel 2

r: radius of the wheel 1

For the second wheel you have:

r'=2r

You replace this value of r' in the following equation:

\omega'=\frac{v}{r'}=\frac{v}{2r}=\frac{1}{2}\frac{v}{r}=\frac{1}{2}\omega\\\\\omega'=\frac{1}{2}\omega

The angular velocity of the second wheel is one half of the angular velocity of the first wheel

6 0
3 years ago
Determine the work for the system that does 106 j of work and releases 74 j of energy
nikitadnepr [17]
Net work = Work done - Amount Work release
W = 106 - 74 = 32 J

In short, Your Answer would be: Either C or D

Hope this helps!
5 0
4 years ago
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lilavasa [31]
The pressure law states that for a constant volume of gas in a sealed container the temperature of the gas is directly proportional to its pressure. This can be easily understood by visualising the particles of gas in the container moving with a greater energy when the temperature is increased.

6 0
3 years ago
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If the density of a diamond is 3.5 g/cm", what would be the mass of a diamond whose
alexandr1967 [171]

Answer:

Explanation:

7 0
4 years ago
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