The minimum coefficient of friction to avoid slippage of the coin is 0.23.
<h3>
Minimum coefficient of friction</h3>
The minimum coefficient of friction can determined from the maximum speed of the coin.
ma = μmg
mv²/r = μmg
v²/r = μg
v² = μgr
μ = v²/(gr)
μ = (ωr)²/(gr)
μ = ω²r/g
μ = (7.95² x 0.035)/(9.8)
μ = 0.23
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Answer
I think most see black and white.
(a) The total momentum of the system before the train cars collide is 1,600 kgm/s.
(b) The total momentum of the system be after the train cars collide is 1,600 kgm/s.
<h3>What is the total momentum of the car system before the collision?</h3>
The total momentum of the car system before the collision is determined by applying the formula for linear momentum.
Pi = m₁u₁ + m₂u₂
where;
- m₁ is the mass of the car on the right
- m₂ is the mass of the car on the left
- u₁ is the initial velocity of the right
- u₂ is the initial velocity of the car on the left
Let the rightward direction = positive
Let the leftward direction = negative
Pi = (600 kg x 4 m/s) + (400 kg) x (-2 m/s)
Pi = 2,400 kgm/s - 800 kgm/s
Pi = 1,600 kgm/s
Based on the law of conservation of linear momentum, the sum of the initial momentum of an isolated system is <u>equal</u> to the sum of the final momentum of the system
Pf = Pi = 1,600 kgm/s.
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