Answer:
Increase in temperature = 269.54 °C
Explanation:
We have equation for thermal expansion
ΔL = LαΔT
Change in length, ΔL = 0.08 m
Length, L = 56 m
Coefficient of thermal expansion, α = 5.3 x 10⁻⁶ °C⁻1
Change in temperature, ΔT = T - 253
Substituting
0.08 = 56 x 5.3 x 10⁻⁶ x (T - 253)
(T - 253) = 269.54
T = 522.54 °C
Increase in temperature = 269.54 °C
A heat pump has a coefficient of performance of 7.05. If the heat pump absorbs 20 cal of heat from the cold outdoors in each cycle, find the heat expelled to the warm indoors. Answer in units of cal. I believe COP (heating mode) : 7.05 and COP = Qh/W Qc = 20 cal so I have to find Qh= ? cal I dont know an equation to put all this together? Please help, thank you.
True . this is called a complex substance
A) 5 kg block of wood
B) 100 kg person
C) 412 kg motorcycle
D) 2540 kg elephant
Answer: D