The reaction of sugar with oxygen is as follows:
C₁₂H₂₂O₁₁ + 12 O₂ → 12 CO₂ + 11 H₂O
When in the presence of pure oxygen, sucrose (table sugar) will not form caramel, in fact it will combust into carbon dioxide and water like any other carbohydrate.
Caramel is actually formed by slowly heating sucrose to high temperatures of around 170 °C resulting in thermal decomposition. This essentially removes molecules of water from the sucrose which results in the compound isomerizing and eventually polymerizing to form caramel. The chemical make up of caramel is the same as sucrose, so it will still be composed of carbon, hydrogen and oxygen.
The subscript is the amount of atoms in each molecule and the coefficient is the amount of molecules. there are 4 Hydrogen, 2 Sulfur, and 8 Oxygen in this particular substance.
Answer:
Explanation:
Given that:
The energy of the photon = 2.3 eV
Energy in eV can be converted to energy in J as:
1 eV = 1.60 × 10⁻¹⁹ J
So, Energy = 
Considering
Where,
h is Plank's constant having value 
c is the speed of light having value 
is the wavelength of the light being bombarded
Thus,
Also,
1 m = 10⁻⁹ nm
So,
Red blood cells are formed in the red bone marrow of bones. Stem cells in the red bone marrow called hemocytoblasts give rise to all of the formed elements in blood. If a hemocytoblast commits to becoming a cell called a proerythroblast, it will develop into a new red blood cell.
Answer:
The change in concentration of H+ ions is -9.99×10⁻⁵
Explanation:
When pH rises, we talk about neutralization and, there is a decline in proton's concentration.
pH lower than 7 is acid
pH higher than 7 is basic
Protons are neutralized by hydroxides to make water as this:
H₃O⁺ + OH⁻ ⇄ H₂O
pH = - log [H₃O⁺]
[H₃O⁺] = 10^-pH
In conclussion: [H₃O⁺]₁ = 10⁻⁴ → 1×10⁻⁴
[H₃O⁺]₂ = 10⁻⁷ → 1×10⁻⁷
1×10⁻⁷- 1×10⁻⁴
The change in concentration of H+ ions is -9.99×10⁻⁵
