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4 years ago

the refractive index is the blank of the speed of light in a medium to the speed of light in a vacuum

Physics

2 answers:

andrew11 [14]4 years ago

8 0

Answer:ratio

Explanation:

creativ13 [48]4 years ago

3 0

Answer:

ratio

Explanation:

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1 If you measured the distance travelled by a snail in

Fittoniya [83]

The answer is m/s hope it helps

3 0

2 years ago

2. Starting from the origin, a person walks 4 km east during first day, and 7 km west the

Artemon [7]

The total distance is 4 + 7 = 11 Km

6 0

3 years ago

True or false: objects fall toward earth at a rate of 9.8 m/s because of centripetal force.

Citrus2011 [14]

Sadly, no. The statement kind of has some appropriate words in it, but it's badly corrupted. Objects don't fall to Earth at a rate of 9.8 m/s, and the force that accelerates them downward is not a centripetal one.

4 0

3 years ago

Driving along a crowded freeway, you notice that it takes a time tt to go from one mile marker to the next. When you increase yo

ddd [48]

Answer:

38.6 mi/h

Explanation:

7.4 mi/h = 7.4mi/h * (1/60)hour/min * (1/60) min/s = 0.00206 mi/s

Let v (mi/s) be your original speed, then the time t it takes to go 1 mi/s is

t = 1/v

Since you increase v by 0.00206 mi/s, your time decreases by 15 s, this means

t - 15 = 1/(v+0.00206)

We can substitute t = 1/v to solve for v

$\frac{1}{v} - 15 = \frac{1}{v + 0.00206}$

We can multiply both sides of the equation with v(v+0.00206)

v+0.00206 - 15v(v+0.00206) = v

$-15v^2 - 0.0308v + 0.00206 = 0$

$v= \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

$v= \frac{0.03083\pm \sqrt{(-0.03083)^2 - 4*(-15)*(0.00205)}}{2*(-15)}$

$v= \frac{0.03083\pm0.35}{-30}$

v = -0.01278 or v = 0.01 0724 mi/s

Since v can only be positive we will pick v = 0.010724 mi/s or 0.010724*3600 = 38.6 mi/h

6 0

4 years ago

Running with an initial velocity of +11m/s, a horse has an average acceleration of -1.81m/s 2 . How long does it take for the ho

Ronch [10]

Answer:

2.49 seconds

Explanation:

From the question,

a = (v-u)/t............................ Equation 1

Where a = acceleration, v = final velocity, u = initial velocity, t = time

Make t the subject of the equation

t = (v-u)/a.......................... Equation 2

Given: v = 6.5 m/s, u = 11 m/s, a = -1.81 m/s²

Substitute these values into equation 2

t = (6.5-11)/(-1.81)

t = -4.5/-1.81

t = 2.49 s

6 0

3 years ago