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Arturiano [62]
3 years ago
5

Which situations might cause two observers (A and B) to measure different frequencies for the same vibrating object? Select the

two correct answers. (2 points)
Observer A and Observer B are both stationary and at the same distance from the object.
Observer A and Observer B are both stationary and at the same distance from the object.

Observer A is stationary and Observer B is moving.
Observer A is stationary and Observer B is moving.

Observer A and Observer B are moving at different speeds relative to each other.
Observer A and Observer B are moving at different speeds relative to each other.

Observer A and Observer B are stationary but at different distances from the vibrating object.
Physics
1 answer:
Alex787 [66]3 years ago
6 0

We want to explain why two different observes may measure different frequencies for the same vibrating object.

We will see that the two correct options are:

  • <em>Observer A is stationary and Observer B is moving.</em>
  • <em>Observer A and Observer B are moving at different speeds relative to each other.</em>

<em />

Let's assume that the vibrating object is a guitar string. Thus, the string makes a noise, and from that noise, we can estimate the frequency at which the string vibrates.

Now there appears a really cool effect, called the Doppler Effect. It says that the apparent change of frequency is <u>due to the motion of the observer or the source of the frequency (or both).</u>

For example, if you move towards the vibrating string, the perceived frequency will be larger, and you will hear a "higher" sound.

While if you move away from the string, the opposite happens, and you will hear a "lower" sound.

Then the only thing that impacts in how we perceive the frequency is our velocity relative to the source.

So, why do observers A and B measure different frequencies?

The two correct answers are:

  • <em>Observer A is stationary and Observer B is moving.</em>
  • <em>Observer A and Observer B are moving at different speeds relative to each other.</em>

If you want to learn more, you can read:

brainly.com/question/17107808

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laiz [17]

A paper pinwheel is spinning in the wind.

Which statement is correct about the forces responsible for the rotation?

The components of gravity and the force of wind that point through the pivot are responsible for the rotation.

Only the perpendicular component of wind is responsible for the rotation, because gravity points downward.

Only the perpendicular component of gravity is responsible for the rotation, because wind points toward the pivot.

The perpendicular components of gravity and the force of wind are responsible for the rotation.

Answer:

Only the perpendicular component of gravity is responsible for the rotation because wind points toward the pivot.

Explanation:

A pinwheel is a plaything that is made up of paper that is designed to spin when the wind comes in contact with it. The paper is held fast to its axle by a pin which enables it to spin.

Therefore, if the pinwheel is spun anti-clockwise, it brings electrical energy, converting the wind energy and <u>only the perpendicular component of gravity is responsible for the rotation because wind points toward the pivot. </u>

6 0
3 years ago
When the sun provides energy for photosynthesis, an interaction with the __________ takes place.
geniusboy [140]
Answer: chloroplast

Explanation:
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7 0
3 years ago
Rank the deformations of the following rods in terms of the magnitude of the average normal strain: (a) The length of a 1-m-long
kipiarov [429]

To solve this problem we will consider the concepts related to the normal deformation on a surface, generated when the change in length is taken per unit of established length, that is, the division between the longitudinal fraction gained or lost, over the initial length. In general mode this normal deformation can be defined as

\epsilon = \frac{\delta}{l} = \frac{l_0-l}{l}

Here,

\delta= Change in final length (l_0) and the initial length l

PART A)

\epsilon = \frac{\delta_1}{l}

\epsilon = \frac{l_0-l}{l_0}

\epsilon = \frac{1.02-1}{1}

\epsilon = 0.01961

PART B)

\epsilon = \frac{\delta_1}{l}

\epsilon = \frac{l_0-l}{l_0}

\epsilon = \frac{2-1.05}{2}

\epsilon = 0.475

PART C)

\epsilon = \frac{\delta_1}{l}

\epsilon = \frac{l_0-l}{l_0}

\epsilon = \frac{3.07-3}{3}

\epsilon = 0.0233

Therefore the rank of this deformation would be  B>C>A

7 0
3 years ago
An ice skater accelerates backwards for 5.0 seconds to a final speed of 12 m/s. If the acceleration backwards was at a rate of 1
Lostsunrise [7]

Answer:

Vo = 4.5 [m/s]

Explanation:

In order to solve this problem, we must use the following equation of kinematics.

v_{f}=v_{o}+a*t

where:

Vf = final velocity = 12 [m/s]

Vo = initial velocity [m/s]

a = acceleration = 1.5 [m/s²]

t = time = 5 [s]

Now replacing:

12=v_{o}+1.5*5\\v_{o}=12- (7.5)\\v_{o}= 4.5[m/s]

4 0
3 years ago
Caroline, a piano tuner, suspects that a piano's G4 key is out of tune. Normally, she would play the key along with her G4 tunin
alexira [117]

Answer:

e. 425.9 Hz

Explanation:

The computation of the frequency is being played by the out-of-tune key is shown below;

Given that

Δf1  = x - 349.2 = 76.7.........(1)

Δf2 = 440 - x  = 14.1......(2)

Now solve (1) and (2)

(440 - x) - x + 349.2 = 14.1 - 76.7

789.2 + (-2x) = -62.6

x = 425.9 Hz

Hence, the frequency is being played by the out-of-tune key is 425.9 Hz

Therefore the option e is correct

6 0
3 years ago
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