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4 years ago

Only the smallest particles of soil can be displaced by suspension because

2 answers:

mote1985 [20]4 years ago

7 0

The choices can be found elsewhere and as follows:

a. they are so small that they stay close to the ground due to the attractive properties of charged soil particles.

b. they are easily carried by the wind.

c. they easily dissolve in liquid droplets.

d. it is easier for then to roll along the small crevices in the ground.

I think the correct answer from the choices listed above is option B. Only the smallest particles of soil can be displaced by suspension because they are so small that they are easily carried by the wind. Hope this answers the question. Have a nice day. Feel free to ask more questions.

densk [106]4 years ago

3 0

the answer is b-they are easily carried by wind.

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What do repeated trails in an experiment allow scientists to do?

fredd [130]

Answer:

Explanation:

When we do multiple trials of the same experiment, we can make sure that our results are consistent and not altered by random events. Multiple trials can be done at one time. If we were testing a new fertilizer, we could test it on lots of individual plants at the same time.

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3 years ago

An example of acceleration

TEA [102]

Answer:

Explanation:

Newton’s Second Law of Motion says that acceleration (gaining speed) happens when a force acts on a mass (object). Riding your bicycle is a good example of this law of motion at work. Your bicycle is the mass.

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3 years ago

A strip of copper 150 μm thickand 4.5 mm wide is placed in a uniform magnetic field B (vector) ofmagnitude 0.65 T, with B (vecto

kykrilka [37]

Answer:

$V_H=7.3544\times 10^{-6} \,V$

Explanation:

Given that:

thickness of the metal strip, $d=150\times 10^{-6} m$

width of the metal strip, $w=4.5\times 10^{-3}m$

magnitude of the perpendicular magnetic field, $B=0.65 \,T$

current through the strip, $I=23\,A$

charge density, $n=8.47\times 10^{28} \,electrons\,per\,m^3$

Hall voltage is a transverse voltage given by:

$V_H=\frac{I.B}{n.e.d}$

putting the respective values

$V_H=\frac{23\times 0.65}{(8.47\times 10^{28})\times 1.6\times 10^{-19}\times (150\times 10^{-6} )}$

$V_H=7.3544\times 10^{-6} \,V$

Note:

V = E d is used when a charge is moved in a uniform electric field between the two oppositely charged plates, it can't be used here because it is the case of Hall effect where the small voltage develops transverse to the direction of current flow.

6 0

3 years ago

On the International Space Station an object with mass m = 280 g is attached to a massless string L = 0.97 m. The string can han

katovenus [111]

Answer:

5.16 m/s

Explanation:

The tension in the string provides the centripetal force that keeps the object spinning in circular motion, therefore we can write:

$T=m\frac{v^2}{r}$

where

T is the tension

m is the mass of the object

v is the speed

r is the radius of the circle

Here we have:

m = 280 g = 0.280 kg

r = L = 0.97 m (the radius of the circle is the length of the string)

The maximum tension allowed is

T = 7.7 N

Therefore, by solving for v, we find the maximum speed allowed before the string breaks:

$v=\sqrt{\frac{Tr}{m}}=\sqrt{\frac{(7.7)(0.97)}{.280}}=5.16 m/s$

6 0

3 years ago

Can someone plz check if what I typed is good :)

pochemuha

Answer:

Explanation:

6 0

3 years ago