When the system is experiencing a uniformly accelerated motion, there are a set of equations to work from. In this case, work is energy which consist solely of kinetic energy. That is, 1/2*m*v2. First, let's find the final velocity.
a = (vf - v0)/t
2.6 = (vf - 0)/4
vf = 10.4 m/s
Then W = 1/2*(2100 kg)*(10.4 m/s)2
W = 113568 J = 113.57 kJ
Answer: Yos
Explanation: Becouse i experimented that btw
<span>vf^2 = vi^2 + 2*a*d
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vf = velocity final
vi = velocity initial
a = acceleration
d = distance
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since the airplane is decelerating to zero, vf = 0
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0 = 55*55 + 2*(-2.5)*d
d = (-55*55)/(2*(-2.5))
d = 605 meters
</span>
Answer:
Explanation:
The variables we know and are given are:
time, t = 20s
Charge, Q = 3x1-^-6 electrons, which is just 3x10^-6C (C stands for Coulombs, which is the unit for Charge)
We need to find the current, I, and since we know Q and t we can substitute these values into the given equation:
I=Q/t (which if you look at what the RHS is saying, its Charge over time, or more literally means the amount of charge passing a point over a period of time)
If we substitute these values, we will get I as:
I = Q / t
I = 3x10^-6 / 20
I = 1.5x10^-7 A
Hope this helps!
This is kinda confusing. I wish u just to a screenshot of the problem but here goes...
Forest at highest latitudes- Hardwood trees/deer, squirrel, foxes
Praries/temperate climate- Mostly small mammals/scrubs/steppes
High humidity/rainfall near equator- Abundant thick vegatation/manny species
No trees/ polar bears/ mosses- 25cm rain/few animals
