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3 years ago

Which of these experimental designs could lead to bias?

2 answers:

5 0

C is biased because the people were paid to evaluate the car. They are more likely to say better things about it than if they weren't paid.

bulgar [2K]3 years ago

3 0

I believe it is B. The meaning of bias is prejudice in favor or against someone or a group compared to another in an unfair way. Many can have a one sided opinion about something such as who is going to win the race. However, choosing different cheese is more of an opinion showing which they prefer more than being bias.

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A medication 60 mg is ordered. the vial is labeled 1 gm/ 10 ml. How many ml would you give?

timofeeve [1]

I believe it is 6ml because you do the doseage times the ml and mutiply it by 1

4 0

3 years ago

How many grams of iron(III) oxide would be required to make 187 g of iron

enyata [817]

Answer:267 g

Explanation:

4 0

3 years ago

Please answer 11 and 12, I'm not sure of my answers and I'm gonna be tested on this tomorrow. Thanks!

Novay_Z [31]

11. I would say physical because the color of the item is changed and the texture and density is changed aswell.

8 0

3 years ago

Will mark the brainiest later for correct answers! Please show work.

Elodia [21]

Answer:

According to avogadro's law, 1 mole of every substance contains avogadro's number $6.023\times 10^{23}$ of particles and weighs equal to its molecular mass.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

$\text{Number of moles}=\frac{\text{Given molecules}}{\text {Avogadros number}}$

a. moles in 14.08 g of $C_{12}H_{22}O_{11}$ = $\frac{14.08g}{342.3g/mol}=0.04113moles$

molecules in 14.08 g of $C_{12}H_{22}O_{11}$ = $0.04113\times 6.023\times 10^{23}=0.2477\times 10^{23}$

b. moles in 17.75 g of NaCl = $\frac{17.75g}{58.5g/mol}=0.3034moles$

molecules in 17.75 g of $NaCl$ = $0.3034\times 6.023\times 10^{23}=1.827\times 10^{23}$

formula units 17.75 g of $NaCl$ = $0.3034\times 6.023\times 10^{23}=1.827\times 10^{23}$

c. moles in 20.06 g of $CuSO_4.5H_2O$ = $\frac{20.06g}{249.68g/mol}=0.08034moles$

formula units in 20.06 g of $CuSO_4.5H_2O$ = $0.08034\times 6.023\times 10^{23}=0.4839\times 10^{23}$

7 0

3 years ago

What term is used to describe alkaline hydrolysis of fats and oils

Gnesinka [82]

Answer:

Saponification

Explanation:

When treated with a base such as NaOH, the ester is transformed back to alcohol and the sodium salt of carboxylic acid. Saponification is the name <u>given</u> to the reaction since it is utilized in the production of soap.

8 0

2 years ago