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3 years ago

Explain how the addition of thermal energy (heat) from matter affects its particles

Chemistry

1 answer:

MakcuM [25]3 years ago

8 0

Answer:

when a substance is heated it gains thermal energy. Therefore its particles move faster and its temperature rises. when a substance is cool it loses thermal energy which causes its particles to move more slowly and its temperature to drop

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Solutions with water as the solvent are called

Soloha48 [4]

Answer:

C. Aqueous Solutions

General Formulas and Concepts:

<u>Aqueous Solutions</u>'

Dissociation
Solvents and Solutions

Explanation:

Water is the universal solution that solvents are dissolved in. Whenever anything is dissolved in water, it will be an aqueous solution.

Strong ionic solutions dissolve into their ions when dissolved in water.

Weak acids and bases don't fully dissociate in water.

8 0

2 years ago

Consider the insoluble compound silver bromide , AgBr . The silver ion also forms a complex with ammonia . Write a balanced net

Degger [83]

Answer:

- $AgBr(s)+2NH_3(aq)\rightleftharpoons Ag(NH_3)_2^+(aq)+Br^-(aq)$

- $K=1.2x10^{-5}$

Explanation:

Hello,

In this case, by considering the dissolution of silver bromide:

$AgBr(s)\rightleftharpoons Ag^+(aq)+Br^-(aq) \ \ \ Ksp=[Ag^+][Br^-]=7.7x10^{-13}$

And the formation of the complex:

$Ag^+(aq)+2NH_3(aq)\rightleftharpoons Ag(NH_3)_2^+(aq)\ \ \ Kf=\frac{[Ag(NH_3)_2^+]}{[Ag^+][NH_3]^2}=1.6x10^7$

We obtain the balanced net ionic equation by adding the aforementioned equations:

$AgBr(s)+Ag^+(aq)+2NH_3(aq)\rightleftharpoons Ag(NH_3)_2^+(aq)+Br^-(aq)+Ag^+(aq)\\\\AgBr(s)+2NH_3(aq)\rightleftharpoons Ag(NH_3)_2^+(aq)+Br^-(aq)$

Now, the equilibrium constant is obtained by writing the law of mass action for the non-simplified net ionic equation:

$AgBr(s)+Ag^+(aq)+2NH_3(aq)\rightleftharpoons Ag(NH_3)_2^+(aq)+Br^-+Ag^+\\\\K=[Ag^+][Br^-]*\frac{[Ag(NH_3)_2^+]}{[Ag^+][NH_3]^2}$

So we notice that the equilibrium constant contains the solubility constant and formation constant for the initial reactions:

$K=Ksp*Kf=7.7x10^{-13}*1.6x10^{7}\\\\K=1.2x10^{-5}$

Best regards.

4 0

3 years ago

Consider this reaction involving an unknown element X. F2+2XBr⟶Br2+2XF When 1.300 g of XBr reacts, 0.7241 g of Br2 is produced.

scZoUnD [109]

The molar mass of X would be 63.55 g/mol and the chemical symbol of X would be Cu (copper).

From the equation of the reaction: F2+2XBr⟶Br2+2XF

The mole ratio of XBr to Br2 is 2:1

Mole of Br2 = mass/molar mass

= 0.7241/159.808

= 0.004531 mole

Mole of XBr = 2 x mole of Br2

= 2 x 0.004531

= 0.009062 mole

Molar mass of XBr = mass/mole

= 1.300/0.009062

= 143.456 g/mol

Since the molar mass of Br is 79.904, the molar of X would be:

143.456 - 79.904

= 63.55 g/mol

Hence, X would be Cu.

More on molar mass calculation can be found here: brainly.com/question/20691135

6 0

2 years ago

A chemistry student combines 23.0 grams of sodium and 71.0 grams of chloride to form sodium chloride. According to the law of co

Diano4ka-milaya [45]

Answer:

94.0 g.

Explanation:

Hello!

In this case, since the lay of conservation of mass states that energy cannot be neither created nor destroyed, during a chemical reaction it is seen that the reactions undergo a change by which bonds can be broken or formed depending on the case. Thus, for the formation of sodium chloride we evidence the formation of the Na-Cl bond which means sodium is combined with chlorine according to the following chemical reaction:

$2Na(s)+Cl_2(g)\rightarrow 2NaCl(s)$

It means that the reuslting mass of product is:

$m_{NaCl}=23.0+71.0g=94.0g$

Best regards!

8 0

2 years ago

What is the overall equation for FeCl3(aq) + NH3(aq) + H2O(l)? the overall ionic equation? then the net ionic equation?

diamong [38]

So the question ask to calculate the over all equation for a certain element and the following are
- over all equation - FE(OH)3+3NH4CI
- over all ionic equation - e(OH)3 (s) & 3 NH4+ (aq) & 3Cl- (aq) - net ionic equation - Fe+3+3OH-+3NH$++3CI-

4 0

3 years ago

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