1. What happens between the molecules of two objects when a hot object touches a cooler object?
2 answers:
You might be interested in
To plot the calibration curve, you need to prepare iron solutions with known concentrations and measure their absorbance. You need to pipet 0 mL of the diluted solution to have 0.00 mg of iron.
In spectrophotometry, to plot the calibration curve, you need to prepare solutions with known concentrations and measure their absorbance.
We have a standard iron solution with a concentration of 0.2500g/L of pure iron (C₁). We pipet 25.00mL (V₁) of this standard iron solution into a 500mL (V₂) volumetric flask and dilute up to the mark with distilled water.
We can calculate the concentration of the diluted solution (C₂) using the dilution rule.
Then, if we wanted to prepare the blank, that is, the solution that contains the same matrix but not the analyte, and whose concentration in iron is 0.00 mg/L, we wouldn't pipet any of the diluted solution.
To plot the calibration curve, you need to prepare iron solutions with known concentrations and measure their absorbance. You need to pipet 0 mL of the diluted solution to have 0.00 mg of iron.
Learn more: brainly.com/question/24195565
Answer:
I. Kindly, see the attached image.
II. The reaction is exothermic.
III. - 51.88 kJ/mol.
IV. The reaction is spontaneous.
Explanation:
I. Draw a possible potential energy diagram of the reaction. Label the enthalpy of the reaction.
- Since the sign of ΔH is negative, the reaction is exothermic reaction.
In an exothermic reaction, the energy of the reactants is higher than that of the products.
<u><em>Kindly see the attached image to show you the potential energy diagram of the reaction.</em></u>
<em>II. Is the reaction endothermic or exothermic? Explain your answer.</em>
- The reaction is exothermic reaction.
- The sign of ΔH indicates wither the reaction is endothermic or exothermic one:
If the sign is positive, the reaction is endothermic.
If the sign is negative, the reaction is exothermic.
Herein, <em>ΔH = - 33.1 kJ/mol, </em>so the reaction is exothermic.
<em>III. What is the Gibbs free energy of the reaction at 25°C? </em>
∵ ΔG = ΔH - TΔS.
Where, ΔG is the Gibbs free energy change (J/mol).
ΔH is the enthalpy change (ΔH = - 33.1 kJ/mol).
T is the temperature (T = 25°C + 273 = 298 K).
ΔS is the entorpy change (ΔS = 63.02 J/mol.K = 0.06302 J/mol.K).
<em>∴ ΔG = ΔH - TΔS</em> = (- 33.1 kJ/mol) - (298 K)(0.06302 J/mol.K) = <em>- 51.88 kJ/mol.</em>
IV. Is the reaction spontaneous or nonspontaneous at 25°C?
The sign of ΔG indicates the spontaneity of the reaction:
If ΔG < 0, the reaction is spontaneous.
If ΔG = 0, the reaction is at equilibrium.
If ΔG > 0, the reaction is nonspontaneous.
Herein, <em>ΔG = - 51.88 kJ/mol, </em>so the reaction is spontaneous.
