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Vinvika [58]
3 years ago
11

HELP ME ASAP PLEASEEEE

Chemistry
1 answer:
Hunter-Best [27]3 years ago
8 0

Answer:

V_2=435.4L

Explanation:

Hello there!

In this case, for this gas problem, we can use the Avogadro's law as a way to understand the volume-mole behavior as a directly proportional relationship:

\frac{V_2}{n_2}=\frac{V_1}{n_1}

Thus, given the initial and final moles and the initial volume, we obtain the following final volume:

V_2=\frac{V_1n_2}{n_1} =\frac{100.L*14.15mol}{3.25mol}\\\\V_2=435.4L

Best regards.

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The student is now told that the four solids, in no particular order, are aluminum chloride (AlCl3), sugar (C6H12O6), benzoic ac
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Answer:

AlCl₃, NaBr, C₆H₅COOH, C₆H₁₂O₆.

Explanation:

The more ions in solution, the greater the conductivity of a solution because these charged particles can carry electrons in the solution.

In the first place, when AlCl₃ dissolves in water it produces 4 ions:

AlCl₃(aq) ⇄ Al³⁺(aq) + 3 Cl⁻(aq)

If the solution is 0.20M in AlCl₃, it will be 4 x 0.20M = 0.80M in ions.

Secondly, NaBr is a strong electrolyte (<em>complete ionization</em>) so it produces 2 moles of ions per each mole of NaBr dissolved:

NaBr(aq) ⇄ Na⁺(aq) + Br⁻(aq)

If the solution is 0.20M in NaBr, it will be 2 x 0.20M = 0.40M in ions.

Then, benzoic acid is a weak electrolyte (<em>partial ionization</em>) so it will produce <em>less than</em> 2 moles of ions per each mole of benzoic acid dissolved:

C₆H₅COOH(aq) ⇄ C₆H₅COO⁻(aq) + H⁺(aq)

If the solution is 0.20M in benzoic acid, the solution will be far below 0.40M in ions.

Finally, sugar has only nonpolar covalent bonds so it will produce no ions in solution, thus being a poor electricity conductor.

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Al calentar la mantequilla, esta se transforma en liquido, este cambio se denomina?
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To insert a thermometer into an adapter, use choose. To prepare the thermometer. Then, hold the thermometer choose. The adapter
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In order to get readings throughout the distillation process, a thermometer adapter is used with a temperature probe. Use mineral oil to prepare or make the thermometer suitable before inserting it into the adapter. After that, slowly insert the thermometer into the adaptor while holding it close to it.

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7 0
1 year ago
15. If you dilute a 6 M solution of HCl from 5 mL to 50mL, what is the concentration of this new solution? (M1V1 = M2V2)
Andreyy89

Answer:

B) 0.6M

Explanation:

               I apologize in advance if it is not correct :l

The (M1V1= M2V2) is given for you to plug in the correct numbers so let's jot this down.

                    (M1*V1= M2*V2)

so they give us 6M which would be our (M1), from this we can also conclude that 5mL is also V1; ( if you notice the M1's and V1's are always found next to eachother). This leads us to our 50mL, this would be our V2 because the volume went from 5mL to 50mL. Now lets put this in order based on what we know.

M1= 6M                                (M1*V1= M2*V2)

V1= 5mL

M2= ?

V2= 50mL

now we plug in what we know into the equation to find the unknown (M2)

                   (6M*5mL= M2*50mL)

now we could do the long math, but I don't think your on brainly to do the hard way. so lets keep it simple!

                   We are going to put the 50mL under the (6M*5mL) for division.

                             \frac{(6M*5mL)}{(50mL)} This is honestly MUCH easier, than manually answering. you just put that in the calculator and it'll give you B) 0.6M

                 

   honestly though I might not know what I'm doing cuz im currently doing my test and decided to answer this question ;)

        Good Luck!

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I believe the answer to that is c!!!
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