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Vinvika [58]
3 years ago
11

HELP ME ASAP PLEASEEEE

Chemistry
1 answer:
Hunter-Best [27]3 years ago
8 0

Answer:

V_2=435.4L

Explanation:

Hello there!

In this case, for this gas problem, we can use the Avogadro's law as a way to understand the volume-mole behavior as a directly proportional relationship:

\frac{V_2}{n_2}=\frac{V_1}{n_1}

Thus, given the initial and final moles and the initial volume, we obtain the following final volume:

V_2=\frac{V_1n_2}{n_1} =\frac{100.L*14.15mol}{3.25mol}\\\\V_2=435.4L

Best regards.

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