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3 years ago

N an adiabatic process, what happens when gases in a system are compressed?

Physics

2 answers:

agasfer [191]3 years ago

7 0

Answer:

The temperature of the system increases.

Explanation:

As we know that in adiabatic process the heat transferred to the system must be zero

now by first law of thermodynamics we know that

$Q = \Delta U - W$

now we know that

Q = 0 (for adiabatic process)

now we have

$\Delta U = W$

as we know that gas is compressed so the work is done on the gas which shows W is positive

So here change in internal energy must be positive which shows that temperature must be increased

so correct answer will be

The temperature of the system increases.

den301095 [7]3 years ago

5 0

When a gas is compressed rapidly, temperature increases because temperature and volume of gas are inversely proportional to each other according to gas laws. When a gas is compressed rapidly, its volume decreases leading to increase in temperature.
Also the pressure increase which also increases the randomness of the gas molecules which start to collide more frequently and thus the temperature rises .
just to make you understand what randomness affects - you would have noticed that you often sweat in a small room filled with people but it’s cooler if the same number of people are there in a bigger room.
hope it helps you

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A bird is about 6.26.2 in. long, with a thin, dark bill and a wide, white wing stripe. If the bird can fly 9292 mi with the w

Trava [24]

Answer:

$209$ mph

Explanation:

$V$ = Speed of bird in still air

$v$ = Speed of wind = 44 mph

Consider the motion of the bird with the wind

$D_{1}$ = distance traveled with the wind = 9292 mi

$t_{1}$ = time taken to travel the distance with wind

Time taken to travel the distance with wind is given as

$t_{1} = \frac{D_{1}}{V + v}$

$t_{1} = \frac{9292}{V + 44}$ eq-1

Consider the motion of the bird with the wind

$D_{2}$ = distance traveled against the wind = 6060 mi

$t_{2}$ = time taken to travel the distance against wind

Time taken to travel the distance against wind is given as

$t_{2} = \frac{D_{2}}{V + v}$

$t_{2} = \frac{6060}{V - 44}$ eq-2

As per the question,

Time taken with the wind = Time taken against the wind

$t_{1} = t_{2}$

$\frac{9292}{V + 44} = \frac{6060}{V - 44}$

$(9292) (V - 44) = (6060) (V + 44)$

$9292V - 408848 = 6060V + 266640$

$3232V = 675488$

$V = 209$ mph

5 0

2 years ago

<img src="https://tex.z-dn.net/?f=2.25%20%5Ctimes%2030" id="TexFormula1" title="2.25 \times 30" alt="2.25 \times 30" align="absm

Paraphin [41]

67.5 is the answer i believe!!

7 0

2 years ago

Read 2 more answers

What is the formula for velovity?

GarryVolchara [31]

Answer:

if it's velocity u talking of.....

Explanation:

then it's displacement/ time

4 0

2 years ago

The magnitude of the electric field between two parallel charged plates is 200. An electron moves to the negative plate 5. 0 cm

Mama L [17]

The potential difference between the two ends of the circuit is the electric potential difference. The electric potential difference and the work will be 10V and 1.6 x 10^-18 J respectively.

<h3>What is an electric field?</h3>

An electric field is an electric property that is connected with any location in space where a charge exists in any form. The electric force per unit charge is another term for an electric field.

The given data in the problem is given by;

E is the electric field = (200 N/C)

d is the distance = 5.0 cm.=0.05 m

Q is the charge of electrons= 1.602 x 10^-19 C

The formula for electric potential is given by;

$\rm V=Ed$

$\rm V=Ed \\\\ \rm V=200 \times 0.05 \\\\ \rm V= 10 \frac{Nm}{C} = 10 \frac{J}{C} = 10 V.$

The work is defined as the product of the potential difference and charge of an electron.

$\rm W= 10 \times 1.602 x 10^{-19} \\\\\ \rm W= 1.6 x 10^{-18 }J$

Hence the electric potential difference and the work will be 10V and 1.6 x 10^-18 J respectively.

To learn more about the electric field refer to the link;

brainly.com/question/15071884

8 0

2 years ago

Muons are elementary particles that are formed high in the atmosphere by the interactions of cosmic rays with atomic nuclei. Muo

uysha [10]

Answer:

<em>Muons reach the earth in great amount due to the relativistic time dilation from an earthly frame of reference.</em>

Explanation:

Muons travel at exceedingly high speed; close to the speed of light. At this speed, relativistic effect starts to take effect. The effect of this is that, when viewed from an earthly reference frame, their short half life of about two-millionth of a second is dilated. The dilated time, due to relativistic effects on time for travelling at speed close to the speed of light, gives the muons an extended relative travel time before their complete decay. So <em>in reality, the muon do not have enough half-life to survive the distance from their point of production high up in the atmosphere to sea level, but relativistic effect due to their near-light speed, dilates their half-life; enough for them to be found in sufficient amount at sea level. </em>

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3 years ago