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IrinaVladis [17]
2 years ago
12

Based on the information in the graph, why is energy released during the fusion of hydrogen (H) into helium (He)?

Physics
1 answer:
MrMuchimi2 years ago
7 0

Answer:

D

Explanation:

Just had the same question and couldnt find and answer so i guessed. heres the answer no lol!

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A projectile is launched with a velocity of 13.2m/s at an angle of 37 degrees above the horizontal. What is the horizontal compo
MrRissso [65]

Answer:

horizontal component = 10.54m/s

Explanation:

horizontal component = 13.2cos37°

horizontal component = 10.54m/s

8 0
2 years ago
A student throws a water balloon with speed v0 from a height h = 1.82 m at an angle θ = 29° above the horizontal toward a target
3241004551 [841]

Answer:

v_o = 7.76 m/s

Explanation:

As we projected the balloon at speed vo at an angle of 29 degree

so the two component of velocity is given as

v_x = v_ocos29 = 0.875 v_o

v_y = v_o sin29 = 0.485 v_o

now we know that in x direction we have

d = v_x t

7.5 = 0.875 v_o t

v_o t = 8.57

in y direction we have

- 1.82 = (0.485 v_o) t - \frac{1}{2}gt^2

-1.82 = 0.485(8.57) - 4.9 t^2

t = 1.1 s

now we have

v_o = 7.76 m/s

7 0
3 years ago
Which statement accurately compares the heating and cooling rates for water and land?
AVprozaik [17]

Answer:

C is the answer Hope I helped

6 0
3 years ago
Read 2 more answers
If the wave speed stays the same, which of the following decreases as the frequency increases?
dalvyx [7]

Answer:yes

Explanation:

8 0
3 years ago
The hot glowing surfaces of stars emit energy in the form of electromagnetic radiation. It is a good approximation to assume e =
Svetllana [295]

Answer:

Explanation:

(a) Rigel, 2.7x10^32W, T = 11,000K

But L = 4pR²sT⁴

L = 2.7x10^32W, T = 11,000K, s= 5.67 x 10^-8, R= radius in meters

Rigel parallax, p = 0.00378 arc sec

Substituting the various values and making R the subject of the formula

R² = L/(4psT⁴)

R² = 2.7x10^32/(4 x 0.003878 x 5.67x10^-8 x (11,000)⁴)

R² = 2.7x10^32/1.2877x10^7

R² = 2.096761668 x 10^25

R = 4.579041021 x 10^12meters

(b)

Procyon B, 2.1x10^23W, T = 10,000K

But L = 4pR²sT⁴

L = 2.1x10^23W, T = 10,000K, s= 5.67 x 10^-8, R= radius in meters

Procyon B parallax, p = 0.00284 arc sec

R² = 2.1x10^23/(4 x 0.00284 x 5.67x10^-8 x (10,000)⁴)

R² = 2.1x10^23/(6.441 x 10^6)

R² = 3.26036 x 10^16

R = 1.80565 x 10^8 meters

(c) The radius of Rigel is given as 4.579041021 x 10^12meters and the radius of Procyon B is given by 1.80565 x 10^8 meters shows the remarkable difference between a super-giant star(Rigel) and a white dwarf star (Procyon B)

The radius of the sun a red star is 6.96 x 10^8meters which shows a certain level of resemblance with the size of a dwarf white star Procyon B.

The sun is larger than Procyon B as estimated above.

7 0
3 years ago
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