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denis23 [38]
3 years ago
14

Exam number: 007170RR

Chemistry
1 answer:
AleksandrR [38]3 years ago
5 0

Answer:

A open

Explanation:

I am not sure but i think it is!

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What is the molecule that formed between B and F?
Alik [6]

Answer:

BF3

Explanation:

For this question, you need to use the number of valence electrons present in each element. Boron is in group 3/13 on the periodic table so you know it has 3 valence electrons while Fluorine is in group 7/17 so it has 7 valence electrons. These elements are both covalent so they will share electrons. All elements in the first three rows want to reach either have 8 valence electrons or zero valence electrons depending on whichever is easier. When B and F interact each Fluorine will only want to take one electron, but Boron wants to get rid of all 3 electrons, so it will bond with 3 Fluorine to get rid of all its valence electrons.

I hope this helps.

5 0
3 years ago
Calculate the density of carbon dioxide at STP
Artist 52 [7]

Answer:

Density = mass/volume

= 44/22.4

= 1.96 gram/liter

The density of the Carbon Dioxide at S.T.P. (Standard Temperature and Volume) is 1.96 gram/liter.

5 0
3 years ago
What type of physical weathering is caused by the expansion of water?
skelet666 [1.2K]

Answer:

wedging

Explanation:

ice or frost wedging

6 0
3 years ago
Electromagnetic waves heat earths surface through convection?
larisa86 [58]
Heat moves in three ways:Radiation, conduction, and convection. Radiation happens when heat moves as energy waves, call infrared waves,directly from its source to something else.This is how the heat from the Sun gets to Earth.In fact,all hot things radiate heat to cooler things:).hope this helps
4 0
3 years ago
A sample compound contains 5.723g Ag, 0.852g S and 1.695g O. Determine its empirical formula.
Lubov Fominskaja [6]

Answer:

Ag_2SO_4

Explanation:

Formula for the calculation of no. of Mol is as follows:

mol=\frac{mass\ (g)}{molecular\ mass}

Molecular mass of Ag = 107.87 g/mol

Amount of Ag = 5.723 g

mol\ of\ Ag=\frac{5.723\ g}{107.87\ g/mol} =0.05305\ mol

Molecular mass of S = 32 g/mol

Amount of S = 0.852 g

mol\ of\ S=\frac{0.852\ g}{32\ g/mol} =0.02657\ mol

Molecular mass of O = 16 g/mol

Amount of O = 1.695 g

mol\ of\ O=\frac{1.695\ g}{16\ g/mol} =0.10594\ mol

In order to get integer value, divide mol by smallest no.

Therefore, divide by 0.02657

Ag, \frac{0.05305}{0.02657} \approx 2

S, \frac{0.02657}{0.02657} \approx 1

O, \frac{0.10594}{0.02657} \approx 4

Therefore, empirical formula of the compound = Ag_2SO_4

7 0
3 years ago
Read 2 more answers
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