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denis23 [38]
3 years ago
14

Exam number: 007170RR

Chemistry
1 answer:
AleksandrR [38]3 years ago
5 0

Answer:

A open

Explanation:

I am not sure but i think it is!

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To determine the concentration of ethanol in cognac a 5.00 mL sample of the cognac is diluted to 0.500 L. Analysis of the dilute
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Answer : The molar concentration of ethanol in the undiluted cognac is 8.44 M

Explanation :

Using neutralization law,

M_1V_1=M_2V_2

where,

M_1 = molar concentration of undiluted cognac = ?

M_2 = molar concentration of diluted cognac = 0.0844 M

V_1 =  volume of undiluted cognac = 5.00 mL = 0.005 L

V_2 = volume of diluted cognac = 0.500 L

Now put all the given values in the above law, we get molar concentration of ethanol in the undiluted cognac.

M_1\times 0.005L=0.0844M\times 0.500L

M_1=8.44M

Therefore, the molar concentration of ethanol in the undiluted cognac is 8.44 M

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