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3 years ago

Convert 349.5 inches to meters

1 answer:

3 0

1 inch is equivalent to 0.0254 meters. To find the answer, multiply the number of inches by 0.0254.
349.5 x 0.0254 = 8.8773

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At which temperature would a can of soda be most fizzy when it is opened? 30°C 40°C 20°C 10°C

Helga [31]

The answer to your question is 40° because freezing temp for a liquid is 32°

4 0

2 years ago

Read 2 more answers

A gas mixture containing oxygen, nitrogen, and carbon dioxide has a total pressure of 32.5 kPa. If Po2 =

HACTEHA [7]

Answer:

A gas mixture containing oxygen, nitrogen, and carbon dioxide has a total pressure of 32.5 kPa.

<u>The pressure for oxygen is 3 kPa</u>

Explanation:

According to Dalton's Law of Partial Pressure total exerted by the mixture of non-reacting gases is equal to sum of the partial pressure of each gas.

$P_{total}=P_{1}+P_{2}+P_{3}$

So,

For , a gas mixture containing oxygen, nitrogen, and carbon dioxide has a total pressure:

$P_{total}=P_{O_{2}}+P_{N_{2}}+P_{CO_{2}}$

$P_{total} = 32.5kPa$

$P_{O_{2}} = 6.5kPa$

$P_{N_{2}} = 23.0kPa$

Insert the values in :

$P_{total}=P_{O_{2}}+P_{N_{2}}+P_{CO_{2}}$

$32.5 kPa = 6.5 kPa + 23.0 kPa +P_{CO_{2}}$

$32.5 kPa = 29.5 kPa +P_{CO_{2}}$

$P_{CO_{2}}= 32.5 - 29.5$

$P_{CO_{2}}= 3kPa$

6 0

3 years ago

How many moles of water are there in 1.000 l at stp? assume the density of water is 1000 kg/m3?

EastWind [94]

Assume 1 liter = 1 kilogram of water = 1000 grams of water.

Part A)
MW of hydrogen is 1.008g/mol, and oxygen is 16.00g/mol.

Find the MW of water by
2*(1.008) + (16.00) = 18.016g/mol.

Convert 1000g H2O to moles :

(1000g H2O)*(1mol H2O / 18.016g H2O) = 55.51 mol

Part B)
Using the answer from part A and Avogadro's number:

(55.51mol)*(6.022*10^23) =

3.343*10^25 molecules.
Hope this is helpful

7 0

3 years ago

How many grams of sulfuric acid is needed to neutralize 380 ml of solution with pH = 8.94

erma4kov [3.2K]

Answer : The mass of sulfuric acid needed is $16.23\times 10^{-5}g$ .

Solution : Given,

pH = 8.94

Volume of solution = 380 ml = $380\times 10^{-3}$ $(1ml=10^{-3}L)$

Molar mass of sulfuric acid = 98.079 g/mole

As we know,

$pH+pOH=14\\pOH=14-8.94=5.06$

$pOH=-log[OH^-]$

$5.06=-log[OH^-]$

$[OH^-]=0.00000871=8.71\times 10^{-6}mole/L$

Now we have to calculate the moles of $OH^-$ .

Formula used : $Moles=Concentration\times Volume$

$\text{ Moles of }[OH^-]=\text{ Concentration of }[OH^-]\times Volume\\\text{ Moles of }[OH^-]=(8.71\times 10^{-6}mole/L)\times (380\times 10^{-3}L)=3309.8\times 10^{-9}moles$