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joja [24]
3 years ago
13

What is the molecular formula of a compound given the molar mass of the compound is 62.18 g/mol and the empirical formula is c2h

7?
Chemistry
1 answer:
Mariulka [41]3 years ago
5 0
To get the molecular formula we use the individual atomic masses of the atoms making the molecule. Hence, to get the factor by which the empirical formula is multiplied, we divide molar mass by the total of the mass of the atoms making the empirical formula.
(C2H7) the mass of one carbon atoms is 12 so two atoms add up to 24. The mass of one hydrogen atom is 1 a.m.u thus 7 atoms give a total of 7 a.m.u. The sum of the two types of atoms is 24+7= 31
Molar mass=62.18
62.18/31=2.0
Hence, (C2H7) 2=C4H14
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A sample of ammonia is found to occupy 0.250 L under laboratory conditions of 27 °C and 0.850 atm. Find the volume of this sampl
Rzqust [24]

Answer:

0.193 L

Explanation:

Step 1:

Data obtained from the question.

Initial Volume (V1) = 0.250 L

Initial temperature (T1) = 27°C

Initial pressure (P1) = 0.850 atm

Final volume (V2) =?

Final temperature (T2) = 0°C

Final pressure (P2) = 1.00 atm

Step 2:

Conversion of celsius temperature to Kelvin temperature.

Temperature (Kelvin) = temperature (celsius) + 273

Initial temperature (T1) = 27°C = 27°C + 273 = 300K

Final temperature (T2) = 0°C = 0°C + 273 = 273K

Step 3:

Determination of the new volume of the sample of ammonia gas.

The new volume can be obtain by using the general gas equation as shown below:

P1V1/T1 = P2V2/T2

0.850x0.250/300 = 1xV2/273

Cross multiply to express in linear form

300 x V2 = 0.850x0.250x273

Divide both side by 300

V2 = (0.850x0.250x273) /300

V2 = 0.193 L

Therefore, the volume of the sample at 0 °C and 1.00 atm is 0.193 L

6 0
3 years ago
Is N2H4 polar, nonpolar, or ionic?
Fynjy0 [20]
<span>N2H4 is a polar molecule </span>
7 0
4 years ago
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Silver chloride, AgCl (Ksp = 1.8 x 10‒10), can be dissolved in solutions containing ammonia due to the formation of the soluble
Sergeeva-Olga [200]

Explanation:

The given reaction will be as follows.

           AgCl(s) \rightarrow Ag^{+}(aq) + Cl^{-}(aq) ............. (1)

     K_{sp} = [Ag^{+}][Cl^{-}] = 1.8 \times 10^{-10}

Reaction for the complex formation is as follows.

          Ag^{+}(aq) + 2NH_{3}(aq) \rightleftharpoons [Ag(NH_{3})_{2}]^{+}(aq) ........... (2)

          K_{f} = \frac{[Ag(NH_{3})_{2}]}{[Ag^{+}][NH_{3}]^{2}} = 1.0 \times 10^{8}

When we add both equations (1) and (2) then the resultant equation is as follows.

             AgCl(s) + 2NH_{3}(aq) \rightarrow [Ag(NH_{3})_{2}]^{+}(aq) + Cl^{-}(aq) ............. (3)

Therefore, equilibrium constant will be as follows.

                       K = K_{f} \times K_{sp}

                          = 1.0 \times 10^{8} \times 1.8 \times 10^{-10}

                          = 1.8 \times 10^{-2}

Since, we need 0.010 mol of AgCl to be soluble in 1 liter of solution after after addition of NH_{3} for complexation. This means we have to set

               [Ag^{+}] = [Cl^{-}]

                          = \frac{0.010 mol}{1 L}

                          = 0.010 M

For the net reaction, AgCl(s) + 2NH_{3}(aq) \rightarrow [Ag(NH_{3})_{2}]^{+}(aq) + Cl^{-}(aq)

Initial :                             0.010         x                     0                           0

Change :                    -0.010         -0.020             +0.010                +0.010

Equilibrium :                   0            x - 0.020           0.010                 0.010

Hence, the equilibrium constant expression for this is as follows.

              K = \frac{[Ag(NH_{3})^{+}_{2}][Cl^{-}]}{[NH_{3}]^{2}}

     1.8 \times 10^{-2} = \frac{0.010 \times 0.010}{(x - 0.020)^{2}}

             x = 0.0945 mol      

or,          x = 0.095 mol (approx)

Thus, we can conclude that the number of moles of NH_{3} needed to be added is 0.095 mol.

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#3. How does a fever aid an immune response?
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Answer:

it can tell and show what pathogen is in you as well what type and mutation so then your body can fight back and remember the genetic dna so then you will be immune in some way.

Explanation:

8 0
3 years ago
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Answer:

Explanation:

2266mm Hg

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3 years ago
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