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joja [24]
3 years ago
13

What is the molecular formula of a compound given the molar mass of the compound is 62.18 g/mol and the empirical formula is c2h

7?
Chemistry
1 answer:
Mariulka [41]3 years ago
5 0
To get the molecular formula we use the individual atomic masses of the atoms making the molecule. Hence, to get the factor by which the empirical formula is multiplied, we divide molar mass by the total of the mass of the atoms making the empirical formula.
(C2H7) the mass of one carbon atoms is 12 so two atoms add up to 24. The mass of one hydrogen atom is 1 a.m.u thus 7 atoms give a total of 7 a.m.u. The sum of the two types of atoms is 24+7= 31
Molar mass=62.18
62.18/31=2.0
Hence, (C2H7) 2=C4H14
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The empirical formula for trichloroisocyanuric acid, the active ingredient in many household bleaches is OCNCI. The molar mass o
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Answer:

These two are equivalent and valid:

       C_3Cl_3N_3O_3

       Cl_3(CN)_3O_3

Explanation:

The molecular superscripts for each atom in the <em>molecular formula</em> are determined by the number of times that the mass of the<em> empirical formula</em> is contained in the<em> molar mass</em>.

<u />

<u>1. Determine the mass of the empirical formula:</u>

OCNCl:

Atomic masses:

  • O: 15.999g/mol
  • C: 12.011g/mol
  • N: 14.007g/mol
  • Cl: 35.453g/mol

Total mass:

  • 15.999g/mol + 12.011g/mol + 14.007g/mol + 35.453g/mol = 77.470g/mol

<u />

<u>2. Divide the molar mass by the mass of the empirical formula:</u>

  • 232.41g/mol / 77.470g/mol = 3

<u>3. Multiply each superscript of the empirical formula by the previous quotient: 3</u>

       O_3C_3N__3Cl_3

Or:

       C_3Cl_3N_3O_3

You might also write CN as a group:

          Cl_3(CN)_3O_3

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