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3 years ago

How many grams of NA required to react with 75.0 gramsof CL2?

1 answer:

7 0

Cl2 has a molar mass of 71g/mole.
75g/71g/mole=1.06moles of cl2
2Na+Cl2→2NaCl
therefore, for every one mole of cl2 there are 2 moles of Na.
1.06*2=2.12moles of Na
every mole of Na is 22.98g
2.12moles *22.98g/mole= 48.72g Na

answer is 42.72grams

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Answer:

For 1: The correct answer is Option A.

For 2: The correct answer is Option B.

For 3: The correct answer is Option C.

Explanation:

For 1:

Atomic number is defined as the number of electrons or number of protons that are present in a neutral atom. It is represented as Z.

Z = Atomic number = Number of electrons = Number of protons

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Hence, the correct answer is Option A.

For 2:

The isotopic representation of an atom is: $_Z^A\textrm{X}$

where,

Z = Atomic number of the atom

A = Mass number of the atom

X = Symbol of the atom

We are given:

An isotopic representation of beryllium atom: $_4^9\textrm{Be}$

Thus, the number '4' represents the atomic number of beryllium, number '9' represents the mass number of beryllium atom.

Hence, the correct answer is Option B.

For 3:

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In $CO_2$ compound:

Mass of oxygen = 32 g

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Thus, the ratio of mass of oxygen in $CO_2$ and CO is:

$CO_2:CO=32:16=2:1$

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