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timurjin [86]
2 years ago
6

What is the answer pls help me

Chemistry
1 answer:
scZoUnD [109]2 years ago
3 0
It’s definitely magnesium but it may not be
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In a ring structure, an unlabeled atom at the angle where two lines join is assumed to be a carbon atom. 2. unlabeled atoms join
Arte-miy333 [17]

Ring structure is defined as the structure in which one or more series of compounds are joined or linked to form a ring.  Ring can exist in different sizes such as cyclopropane (small ring: three carbon atoms) and cyclohexane (large ring: six carbon atoms).

In ring structure, there is only carbon atoms linked with hydrogen atoms which are identified by the linkage of two lines.

See the attached figure: cyclopropane (unlabelled atoms are carbon atoms with hydogens).

Thus, in ring structure, an unlabelled atom at an angle where two lines joined assumed to be carbon atom.

6 0
2 years ago
Question number 1 they are asking for highest possible theoretical temperature?
den301095 [7]

I think the highest theoretical temperature would be 36.5°C.

Hope I helped, sorry if not.

7 0
3 years ago
If I raise the Celsius scale by 15 degrees, how<br> much will I be raising it in the Kelvin Scale?
Mariana [72]

Answer:

If the change is +15 degrees Celsius, the change is +15 Kelvin (note that it's not degrees Kelvin, just simply Kelvin). You can use the conversion, which is 273.15 Kelvin = zero degrees Celsius. Since it's a relative scale, 10 C = 274.15 K, and 20 C = 275.15 and so forth.

6 0
3 years ago
At 373.15K and 1 atm, the molar volume of liquid water and steamare 1.88 X 10-5 m3 and 3.06 X 10-2m3, respectively. Given that t
professor190 [17]

Answer The value of \Delta H and \Delta U is, 40.79 kJ and 37.7 kJ respectively.

Explanation :

Heat released at constant pressure is known as enthalpy.

The formula used for change in enthalpy of the gas is:

\Delta Q_p=\Delta H=40.79kJ/mol

Now we have to calculate the work done.

Formula used :

w=-P\Delta V\\\\w=-P\times (V_2-V_1)

where,

w = work done  = ?

P = external pressure of the gas = 1 atm

V_1 = initial volume = 1.88\times 10^{-5}m^3=1.88\times 10^{-5}\times 10^3L=1.88\times 10^{-2}L

V_2 = final volume = 3.06\times 10^{-2}m^3=3.06\times 10^{-2}\times 10^3L=3.06\times 10^{1}L

Now put all the given values in the above formula, we get:

w=-(1atm)\times (3.06\times 10^{1}-1.88\times 10^{-2})L

w=-30.5812L.atm=-30.5812\times 101.3J=-3097.87556J=-3.09\times 10^3J=-3.09kJ

Now we have to calculate the change in internal energy.

\Delta U=q+w

\Delta U=40.79kJ+(3.09kJ)

\Delta U=37.7kJ

Thus, the value of \Delta H and \Delta U is, 40.79 kJ and 37.7 kJ respectively.

4 0
3 years ago
Help quick! Will mark brainlest!
Ivenika [448]

Answer: 10HSiCl3 + 15H2O → H10Si10O15 + 30HCl

Explanation:

6 0
2 years ago
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