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sladkih [1.3K]
3 years ago
15

Which answer describes the measure of the amount of matter ?

Chemistry
2 answers:
svet-max [94.6K]3 years ago
7 0
A) molar mass.

Molar mass is the mass of one mole of a pure substance. So basically the measure of the amount of matter
Cerrena [4.2K]3 years ago
7 0

Answer: B. mole/s

Explanation:

Molar mass is defined as the mass of 1 mole of the compound. It is calculated by adding the masses of all the elements present in the compound.

A mole is defined as the amount of substance that contains Avogardro number of the substance. Avogadro's number is given by 6.022\times 10^{23}.

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles. Standard condition of temperature (STP)  is 273 K and atmospheric pressure is 1 atmosphere respectively.

Pressure of the gas is defined as the force exerted by the particles on the walls of the container. It is expressed in various terms like 'mmHg', 'atm', 'kiloPascals' etc..

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The energies of the bonds broken in a certain reaction are greater than the energies of the bonds formed. Which one of the follo
frosja888 [35]

Answer:

a. The reaction is endothermic.

Explanation:

The heat involved in a chemical reaction is given by the enthalpy change (ΔH), which is equal to the balance between the chemical bonds that are broken (release energy) and the chemical bonds that are formed (need energy):

ΔH ≅ bonds broken - bonds formed

If broken bonds > bonds formed ⇒ ΔH > 0 ⇒ endothermic reaction

Therefore, the reaction is endothermic (it requires energy).

4 0
3 years ago
10 To become positively charged, an atom must: A Galn a proton B Lose a proton C С. Galn an electron D Lose an electron } ​
Studentka2010 [4]

Answer:

D: lose an electron

Explanation:

when an atom loses an electron it's positively charged and when it gain an electron it is negatively charged

6 0
3 years ago
Solution of the Schrödinger wave equation for the hydrogen atom results in a set of functions (orbitals) that describe the behav
kvv77 [185]

Answer :

'n' specifies  → (B) The energy and average distance from the nucleus.

'l' specifies   → (C) The subshell orbital shape.

'ml' specifies → (A) The orbital orientation.

Explanation :

Principle Quantum Numbers : It describes the size of the orbital. It is represented by n. n = 1,2,3,4....

Azimuthal Quantum Number : It describes the shape of the orbital. It is represented as 'l'. The value of l ranges from 0 to (n-1). For l = 0,1,2,3... the orbitals are s, p, d, f...

Magnetic Quantum Number : It describes the orientation of the orbitals. It is represented as m_l. The value of this quantum number ranges from (-l\text{ to }+l). When l = 2, the value of

Spin Quantum number : It describes the direction of electron spin. This is represented as m_s. The value of this is +\frac{1}{2} for upward spin and -\frac{1}{2} for downward spin.

As per question we conclude that,

'n' specifies  → The energy and average distance from the nucleus.

'l' specifies   → The subshell orbital shape.

'ml' specifies → The orbital orientation.

5 0
3 years ago
1pt The heaviest concentration of asteroids lies in a belt between
Olegator [25]
The answer is A, Mars and Jupiter.
7 0
3 years ago
Aqueous sulfuric acid reacts with solid sodium hydroxide to produce aqueous sodium sulfate and liquid water . If of sodium sulfa
notka56 [123]

Answer:

27%

Explanation:

Hello,

The following information is missing, but I found it: "1.92 g of sodium sulfate is produced from the reaction of 4.9 g of sulfuric acid and 7.8 g of sodium hydroxide" so the undergoing chemical reaction is:

2NaOH+H_2SO_4-->Na_2SO_4+2H_2O

Now, to compute the percent yield, we must first establish the limiting reagent to subsequently determine the theoretical yield of sodium sulfate because the real (1.92g) is already given, thus, we consider the following procedure:

n_{NaOH}=7.8gNaOH*\frac{1molNaOH}{40gNaOH}=0.2molNaOH\\n_{H_2SO_4}=4.9gH_2SO_4*\frac{1molH_2SO_4}{98gH_2SO_4}=0.050molH_2SO_4\\

- The moles of sodium hydroxide that completely react with 0.05 moles of sulfuric acid are:

0.2molNaOH*\frac{1molH_2SO_4}{2molNaOH}=0.098molH_2SO_4

As this number is higher than the previously computed 0.05 moles of available sulfuric acid, one states that the sulfuric acid is the limiting reagent. Now, the theoretical grams of sodium sulfate are found via:

0.05molH_2SO_4*\frac{1molNa_2SO_4}{1mol H_2SO_4} *\frac{142.04gNa_2SO_4}{1molNa_2SO_4} =7.1gNa_2SO_4

Finally, the percent yield turns out into:

Y=\frac{1.92g}{7.1g} *100

Y=27.0%

Best regards.

6 0
3 years ago
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