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Romashka [77]
4 years ago
6

So2−3(aq)→so2−4(aq) (basic solution) express your answer as a chemical equation. identify all of the phases in your answer. so32

−(aq)+2oh−(aq)→so42−(aq)+h2o(l)+2e− previous answers
Chemistry
1 answer:
alexira [117]4 years ago
6 0

Answer:

SO_{3}^{2-}(aq.)+2OH^{-}(aq.)\rightarrow SO_{4}^{2-}(aq.)+H_{2}O(l)+2e^{-}

Explanation:

The given reaction is an example of oxidation reaction. The step-by-step balancing procedure has been shown below:

Chemical equation: SO_{3}^{2-}(aq.)\rightarrow SO_{4}^{2-}(aq.)

Balance H and O in basic medium: SO_{3}^{2-}(aq.)+2OH^{-}(aq.)\rightarrow SO_{4}^{2-}(aq.)+H_{2}O(l)

Balance charge: SO_{3}^{2-}(aq.)+2OH^{-}(aq.)\rightarrow SO_{4}^{2-}(aq.)+H_{2}O(l)+2e^{-}

Balanced chemical equation:

SO_{3}^{2-}(aq.)+2OH^{-}(aq.)\rightarrow SO_{4}^{2-}(aq.)+H_{2}O(l)+2e^{-}

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3 years ago
In one sample of a compound of copper and oxygen, 3.12g of the compound contains 2.50g of copper and the remainder is oxygen. Ca
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Answer:

% composition O = 19.9%

% composition Cu = 80.1%

Explanation:

Given data:

Total mass of compound = 3.12 g

Mass of copper = 2.50 g

Mass of oxygen = 3.12 - 2.50 = 0.62 g

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Solution:

Formula:

<em>% composition = ( mass of element/ total mass)×100</em>

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% composition O = (0.62 g / 3.12 g)×100

% composition O = 0.199 ×100

% composition O = 19.9%

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