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Maru [420]
3 years ago
10

Which of the following graphs represents constant positive acceleration

Physics
1 answer:
nika2105 [10]3 years ago
5 0
W, because as time is moving up at a consistent rate the speed is as well, creating the straight line.
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Which phrase does not describe a mineral?
Jobisdone [24]

The answer is A) specific chemical consumption

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3 years ago
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What control what enter and leaves the cell in a animal cell
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The Cell Membrane is what controls what enters and leaves the cell.
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3 years ago
A candy-filled piñata is hung from a tree for Elia's birthday. During an unsuccessful attempt to break the 4.4-kg piñata, Tonja
Klio2033 [76]

Answer: v = 0.6 m/s

Explanation: <u>Momentum</u> <u>Conservation</u> <u>Principle</u> states that for a collision between two objects in an isolated system, the total momentum of the objects before the collision is equal to the total momentum of the objects after the collision.

Momentum is calculated as Q = m.v

For the piñata problem:

Q_{i}=Q_{f}

m_{p}v_{p}_{i}+m_{s}v_{s}_{i}=m_{p}v_{p}_{f}+m_{s}v_{s}_{f}

Before the collision, the piñata is not moving, so v_{p}_{i}=0.

After the collision, the stick stops, so v_{s}_{f}=0.

Rearraging, we have:

m_{s}v_{s}_{i}=m_{p}v_{p}_{f}

v_{p}_{f}=\frac{m_{s}v_{s}_{i}}{m_{p}}

Substituting:

v_{p}_{f}=\frac{(0.54)(4.8)}{(4.4)}

v_{p}_{f}= 0.6

Immediately after being cracked by the stick, the piñata has a swing speed of 0.6 m/s.

3 0
3 years ago
In a house 5 bulbs of 25 watts each are used for 6 hours a day.Calculate the unit of electricity consumed in a month of 30 days.
Svetradugi [14.3K]

(5 bulbs) x (25 watt/bulb) x (6 hour/day) x (30 day/month) =

             (5 x 25 x 6 x 30) watt-hour/month =

                 22,500 watt-hour/month .

The most common unit of electrical energy used for billing purposes
is the 'kilowatt-hour' = 1,000 watt-hours .

               22,500 watt-hour/month =  <em>22.5 kWh/month</em>.

             (22.5 kWh/month) x (1.50 Rs/kWh) =  <em>33.75 Rs / month


</em>
4 0
3 years ago
A cricket ball is dropped from a height of 20 m. Calculate: a) the speed of the ball. b) the time it takes to fall through this
AysviL [449]

Answer:

Initial velocity is 0 .. ( since it is just dropped)

now using V²= u² +2gh

=> (Vfinal)² = 0+2*10*20

=> v² = 20*20 = 400

=> v = √400 = 20m/s

for time taken

use V = u+gt

=> t = V/g = 20/10 = 2sec

7 0
2 years ago
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