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Maru [420]
3 years ago
10

Which of the following graphs represents constant positive acceleration

Physics
1 answer:
nika2105 [10]3 years ago
5 0
W, because as time is moving up at a consistent rate the speed is as well, creating the straight line.
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A truck is traveling at 74.5 kilometers per hour away from you. The driver is blowing the horn which has a frequency of 415 Hz.
ArbitrLikvidat [17]
It would be a high pitched sound. Hope this helps.
8 0
3 years ago
(25 pts) Estimate how much collector area and storage capacity would be required for an active solar hot-water system designed t
Aneli [31]

Answer:

The required  total area is 1.48 m²

Explanation:

Given that,

Latitude = 44+° N

New Mexico,

Latitude= 35+° N

Heat capacity = 4200 J/Kg°C

Temperature = 60°C

Let us assume the input temperature 22°C

Estimate volume of water 100 ltr for 4 person.

We need to calculate the heat

Using formula of heat

H=mc_{p}\Delta T

H=mc_{p}(T_{f}-T_{i})

Put the value into the formula

H=100\times4200\times(60-22)

H=15960\ KJ...(I)

Let solar radiation for 6 hours/day.

We need to calculate the total energy per unit area

Using formula of energy

E=1000\times6\times3600\ J/m^2

E=21600\ KJ/m^2

Let the efficiency of collector is 50 %

Then,  the total energy per unit area will be

E=21600\times\dfrac{50}{100}

E=10800\ KJ/m^2....(II)

We need to calculate the required total area

Using equation (I) and (II)

A=\dfrac{H}{E}

Where, H = heat

E = total energy

Put the value into the formula

A=\dfrac{15960}{10800}

A=1.48\ m^2

Hence, The required  total area is 1.48 m²

6 0
3 years ago
Question 4
bagirrra123 [75]

That's <em>false</em>.  It's just the opposite.  As you become more fit, your heart becomes able to accomplish more with each beat, so your resting heart rate DEcreases.

4 0
3 years ago
An object is dropped from a height of 25 meters. At what velocity will it hit the ground?
Goryan [66]
You can use Vf^2-Vi^2 = 2ax

Vf^2 - 0 = 2(9.81)(25)

Or you can use energy

mgh = 1/2mv^2

2gh =v^2

Same thing
6 0
3 years ago
3 A 100 g steel ball falls from a height of 1.8 m on to a metal plate and rebounds to a height of 1.25 m.​
BigorU [14]

Given values:

Mass of the steel ball, m = 100 g = 0.1 kg

Height of the steel ball, h1 = 1.8 m

Rebound height, h2 = 1.25 m

a.  PE= mgh

0.1 x 9.8 x 1.8 =

1.764 Joules

b. KE = PE ->

1.764 Joules

c. KE= 1/2 mv square

so v = square root 2ke/m

square root 2 x 1.764/ 0.1

= 5.93 m/s

d. KE=PE=mgh square

0.1 x 9.8 x 1.21 =

1.186 joules

velocity of rebond is square root 2x 1.186/ 0.1 = 4.87 m/s

6 0
3 years ago
Read 2 more answers
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