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3 years ago

A single proton has which electrical charge?

Physics

2 answers:

Komok [63]3 years ago

8 0

B. A single proton has +1 charge.
*I'm pretty sure*

valentina_108 [34]3 years ago

5 0

The answer is B- a positive charge

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A car slows down from 21 m/s to rest in a distance of 63m. Assuming the car has a constant acceleration, calculate the time it t

vladimir2022 [97]

Answer:

-3.5 m/s²

Explanation:

Initial Velocity = 21m /s
Final velocity = 0m/s
Distance = 63 m .
Acclⁿ = ?

We know that :-

$\longrightarrow$ Stopping distance = u²/2(-a)

$\longrightarrow$ 63m = (21m/s)² / -2a

$\longrightarrow$ a = - 21 * 21 / 63 * 2 m/s²

$\longrightarrow$ a = - 3.5 m/s²

**Edits are welcomed**

5 0

3 years ago

what is the angular speed w of the system immediately after the collision in terms f the sstem parameters and I

denis23 [38]

Answer: hello some part of your question is missing attached below is the missing detail

answer :

wf = M( v cos∅ )D / I

Explanation:

The Angular speed wf of the system after collision in terms of the system parameters and I can be expressed as

considering angular momentum conservation

Li = Lf

M( v cos∅ ) D = ( ML^2 / 3 + mD^2 ) wf

where ; ( ML^2 / 3 + mD^2 ) = I ( Inertia )

In terms of system parameters and I

wf = M( v cos∅ )D / I

5 0

3 years ago

The angle of incidence of a ray of light striking an equilateral triangular prisms ABC of refracting angle 60o is 40o. Calculate

valkas [14]

Answer:

1: the refracted angle in the first face is equal to the incident angle that is 60degrees

2. Emergence Angle is 42degrees

Explanation:

Pls see attached file

5 0

3 years ago

An astronaut holds a rock 100 m above surface of Planet X. The rock is then thrown upwards with a sleek of 15m/s. The rock reach

Gelneren [198K]

Answer: $5 m/s^{2}$

Explanation:

This problem is related to vertical motion, and the equation that models it is:

$y=y_{o}+V_{o}sin\theta t-\frac{1}{2}gt^{2}$ (1)

Where:

$y=0m$ is the rock's final height

$y_{o}=100 m$ is the rock's initial height

$V_{o}=15 m/s$ is the rock's initial velocity

$\theta=90\°$ is the angle at which the rock was thrown (directly upwards)

$t=10 s$ is the time

$g$ is the acceleration due gravity in Planet X

Isolating $g$ and taking into account $sin(90\°)=1$ :

$g=(-\frac{2}{t^{2}})(y-y_{o}-V_{o}t)$ (2)

$g=(-\frac{2}{(10 s)^{2}})(0 m-100 m-(15 m/s)(10 s))$ (3)

$g=5 m/s^{2}$ (4) This is the acceleration due gravity in Planet X

5 0

3 years ago

1. Una pelota rueda hacia la derecha siguiendo una trayectoria en línea recta de modo que recorre una distancia de 10m en 5 s ,

devlian [24]

Answer:

https://youtu.be/ymHHdoCGJOU

8 0

3 years ago