The Boiling point,melting point, surface tension and viscousity will increase while the Vapor pressure will decrease.
<h3 /><h3>What are intermolecular forces?</h3>
Intermolecular forces are the forces that bind two molecules together. Physical properties are affected by the strength of intermolecular forces
An increase in the strength of intermolecular forces increases will lead to an increase in force applied to break the barriers posed by the strength of the molecules.
This increased intermolecular strength will cause a rise in boiling point,melting point, viscousity and surface tension.
The Vapor pressure reduces with increasing intermolecular strength. Vapor pressure is the amount of vapor that is equilibrium with its own liquid or solid. Hence,with increasing intermolecular strength the amount of vapor that is in equilibrium with its own liquid will reduce.
To know more about intermolecular forces follow
brainly.com/question/13588164
#SPJ4
Using the average velocity formula which is total distance divided by total time. If the distance is given in km convert to m then divide by 1000 to get m and if time is given in minutes then divide by 60 to get seconds. And after converting, divide to get your final answer in m/s. Hope that helped!
The answer should be all of the above
Answer:
Explanation:
We shall consider the balance of forearm . The weight is balanced by tension created in the bicep of forearm.
The weight of forearm will act downward . Let it be W. Tension T of bicep will pull the forearm upwards . Bicep muscle is attached at a point between palm and elbow. Its other end is attached with hind arm . If we hold the forearm parallel to ground , weight acts vertically downwards and tension in bicep makes some angle with the vertical . Let it be θ.
Vertical component of tension T
= T cos θ . It will balance W .
T cos θ = W
T = W / cos θ
the value of cos θ will always be less than 1.
so T > W . or
tension in bicep is more than weight of forearm.
Answer:
1234285.7 m or 1234.3 km
Explanation:
Let the distance be 
, the time taken by P waves be 
and the time taken by the S waves be 
.
For the P waves,
For the S waves,
Equating the ,
Divide both sides of the equation by 500 to reduce the terms.
Since S waves arrive 2 minutes (= 120 seconds) after P waves,
Substitute this in the equation of the distance.
Substitute this in the equation for involving .
