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yanalaym [24]
3 years ago
5

Suppose you have thrown a rock nearly straight up at a coconut in a palm tree,and the rock misses on the way up but hits the coc

onut on the way down.Neglecting air resistance,how does the speed of the rock when it hits the coconut on the way down compare with what it would have been if it hits the coconut on the way up?Is is more likely to dislodge the coconut on the way up or down? Explain.
Physics
1 answer:
Margarita [4]3 years ago
5 0
Most likely it would dislodge the coconut on the way down due to gravity because on the way up the gravity would slow down the rock but on they down the gravity pulls the rock
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IF EARTH HAD NO ATMOSPHERE, WOULD A FALLING OBJECT EVER REACH TERMIONAL VELOCITY?
EleoNora [17]
No.  What most people call 'terminal velocity' is the speed of the falling
object when the downward force of gravity is equal to the upward force
of air resistance.  At that speed, the vertical forces on the object are
balanced, so it stops accelerating, and falls at a constant speed.

If there were no atmosphere, there would be no upward force due to
air resistance.  The falling object would continue to accelerate all the
way down until it went 'splat'.

This is exactly the situation for meteoroids or asteroids falling onto the Moon.
3 0
4 years ago
What minimum heat is needed to bring 150 g of water at 20 ∘c to the boiling point and completely boil it away? the specific heat
AnnZ [28]

Try this solution:

if given m=0.15 kg; t₁=20 °C; t₂=100 °C; c=4190 J/(kg*C); q=226*10⁴ J/kg., then


Q=Q₁+Q₂,

where Q₁=cm(t₂-t₁) and Q₂=q*m.

Finally,

Q=cm(t₂-t₁)+qm;

Q=4190*0.15*80+2240000*0.15=386280 J=<u>386.28 kJ</u>.

4 0
3 years ago
A solid circular shaft and a tubular shaft, both with the same outer radius of c=co = 0.550 in , are being considered for a part
Norma-Jean [14]

Answer:

The power for circular shaft is 7.315 hp and tubular shaft is 6.667 hp

Explanation:

<u>Polar moment of Inertia</u>

(I_p)s = \frac{\pi(0.55)4}2

      = 0.14374 in 4

<u>Maximum sustainable torque on the solid circular shaft</u>

T_{max} = T_{allow} \frac{I_p}{r}

         =(14 \times 10^3) \times (\frac{0.14374}{0.55})

         = 3658.836 lb.in

         = \frac{3658.836}{12} lb.ft

        = 304.9 lb.ft

<u>Maximum sustainable torque on the tubular shaft</u>

T_{max} = T_{allow}( \frac{Ip}{r})

          = (14 \times10^3) \times ( \frac{0.13101}{0.55})

          = 3334.8 lb.in

          = (\frac{3334.8}{12} ) lb.ft

          = 277.9 lb.ft

<u>Maximum sustainable power in the solid circular shaft</u>

P_{max} = 2 \pi f_T

          = 2\pi(2.1) \times 304.9

          = 4023.061 lb. ft/s

          = (\frac{4023.061}{550}) hp

          = 7.315 hp

<u>Maximum sustainable power in the tubular shaft</u>

P _{max,t} = 2\pi f_T

            = 2\pi(2.1) \times 277.9

            = 3666.804 lb.ft /s

            = (\frac{3666.804}{550})hp

            = 6.667 hp

7 0
3 years ago
can someone help me answer this? i dont get it and I need help before the next 30 minutes. ill give a brainiest to whoever helps
Zinaida [17]

Answer:

S=5.83...

Explanation:

s=d/t

Speed=distance/time

s=35/10

s=5.83...

3 0
4 years ago
Which describes the position on a horizontal number line
Savatey [412]

Answer:

It is formed by a horizontal number line, called the x-axis, and a vertical number line, called the y-axis.

Explanation:

3 0
3 years ago
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