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Natalija [7]
3 years ago
15

Review the equation below. 2KClO3 mc012-1.jpg 2KCl + 3O2 How many moles of oxygen are produced when 2 mol of potassium chlorate

(KClO3) decompose?
Chemistry
2 answers:
slamgirl [31]3 years ago
5 0

Answer:

the answer is 3

Explanation:

2 mol of potassium chlorate x \frac{3}{2} = 3

also just did it on edge

Vlada [557]3 years ago
4 0
Stoichiometry <span>of the reaction:

</span><span>2 KClO</span>₃<span>    =    2 KCl  +   3 O</span>₂
  ↓                                      ↓
    
2 mole KClO₃ ----------> 3 mole O₂
2 mole KClO₃ ----------> ?

KClO₃ = 2 * 3 / 2

KClO₃ = 6 / 2

= 3 moles de KClO₃

hope this helps!
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600 mph

Explanation:

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Which statement is always true of the cathode in an electrochemical cell? Reduction occurs here. It is considered the "negative"
lara31 [8.8K]

Answer:

It Is Considered The "negative" Electrode

Explanation:

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3 years ago
Calculate the number of moles of H2 produced in the reaction of Mg(s) with HCl(aq). Mg(s) is the
Taya2010 [7]

Explanation:

Moles of metal,

=

4.86

⋅

g

24.305

⋅

g

⋅

m

o

l

−

1

=

0.200

m

o

l

.

Moles of

H

C

l

=

100

⋅

c

m

−

3

×

2.00

⋅

m

o

l

⋅

d

m

−

3

=

0.200

m

o

l

Clearly, the acid is in deficiency ; i.e. it is the limiting reagent, because the equation above specifies that that 2 equiv of HCl are required for each equiv of metal.

So if

0.200

m

o

l

acid react, then (by the stoichiometry), 1/2 this quantity, i.e.

0.100

m

o

l

of dihydrogen will evolve.

So,

0.100

m

o

l

dihydrogen are evolved; this has a mass of

0.100

⋅

m

o

l

×

2.00

⋅

g

⋅

m

o

l

−

1

=

?

?

g

.

If 1 mol dihydrogen gas occupies

24.5

d

m

3

at room temperature and pressure, what will be the VOLUME of gas evolved?

5 0
2 years ago
Reaction is
-Dominant- [34]
According  to the task, you  are proveded with patial pressure of CO2 and graphite, and here is complete solution for the task :
At first you have to find n1 =moles of CO2 and n2 which are moles of C 
<span>The you go :
</span>CO2(g) + C(s) \ \textless \ =\ \textgreater \  2CO(g)

n1 n2 0
-x -x +2x
n1-x n2-x 2x Kp=P^2 (CO)/Pco2
After that you have to use the formula PV=nRT
 Kp=(2x)^2/n1-x
Then you have to solve x, and for that you have to use <span>RT/V
And to find total values:</span>P(total)=n(total)*R*T/V
I am absolutely sure that this would be helpful for you.
7 0
3 years ago
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