Question

Review the equation below. 2KClO3 mc012-1.jpg 2KCl + 3O2 How many moles of oxygen are produced when 2 mol of potassium chlorate (KClO3) decompose?

Answer 1

Answer:

the answer is 3

Explanation:

2 mol of potassium chlorate x $\frac{3}{2}$ = 3

also just did it on edge

Answer 2

Stoichiometry of the reaction:

2 KClO₃    =    2 KCl  +   3 O₂
  ↓                                      ↓
    
2 mole KClO₃ ----------> 3 mole O₂
2 mole KClO₃ ----------> ?

KClO₃ = 2 * 3 / 2

KClO₃ = 6 / 2

= 3 moles de KClO₃

hope this helps!