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Natalija [7]
3 years ago
15

Review the equation below. 2KClO3 mc012-1.jpg 2KCl + 3O2 How many moles of oxygen are produced when 2 mol of potassium chlorate

(KClO3) decompose?
Chemistry
2 answers:
slamgirl [31]3 years ago
5 0

Answer:

the answer is 3

Explanation:

2 mol of potassium chlorate x \frac{3}{2} = 3

also just did it on edge

Vlada [557]3 years ago
4 0
Stoichiometry <span>of the reaction:

</span><span>2 KClO</span>₃<span>    =    2 KCl  +   3 O</span>₂
  ↓                                      ↓
    
2 mole KClO₃ ----------> 3 mole O₂
2 mole KClO₃ ----------> ?

KClO₃ = 2 * 3 / 2

KClO₃ = 6 / 2

= 3 moles de KClO₃

hope this helps!
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Answer:

A shape has 2 pairs of parallel sides and no right angles. What shape is it?

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Explanation:

A shape has 2 pairs of parallel sides and no right angles. What shape is it?

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7 0
2 years ago
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3 years ago
How many grams N2F4 can be produced from 225 g F,?​
zavuch27 [327]

Answer:

308 g

Explanation:

Data given:

mass of Fluorine (F₂) = 225 g

amount of N₂F₄ = ?

Solution:

First we look to the reaction in which Fluorine react with Nitrogen and make N₂F₄

Reaction:

          2F₂ + N₂ -----------> N₂F₄

Now look at the reaction for mole ratio

          2F₂     +    N₂   ----------->  N₂F₄

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As we Know

molar mass of F₂ = 2(19) = 38 g/mol

molar mass of N₂F₄ = 2(14) + 4(19) =

molar mass of N₂F₄ = 28 + 76 =104 g/mol

Now convert moles to gram

                 2F₂          +       N₂   ----------->  N₂F₄

        2 mole (38 g/mol)                        1 mole (104 g/mol)

                 76 g                                           104 g

So,

we come to know that 76 g of fluorine gives 104 g of N₂F₄ then how many grams of N₂F₄ will be produce by 225 grams of fluorine.

Apply unity formula

                  76 g of F₂ ≅ 104 g of N₂F₄

                   225 g of F₂ ≅ X of N₂F₄

Do cross multiplication

                  X of N₂F₄ = 104 g x 225 g / 76 g

                  X of N₂F₄ = 308 g

So,

308 g N₂F₄ can be produced from 225 g F₂

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7 0
3 years ago
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<span>a kilobyte is 2^10 bytes
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</span>
hope this helps
8 0
3 years ago
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