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OverLord2011 [107]
4 years ago
8

can someone please help me with this :) i only have one more try to get it right and if not i get 0/10

Mathematics
2 answers:
Sonja [21]4 years ago
7 0

Answer: \sqrt[5]{27}, fifthroot(27) [according to your picture, I think there will be no space between fifth and root]  

Step-by-step explanation:

concept to know: any exponent that is performed in fraction, the numerator will be the real exponent for the base, while the denominator will be the root

-------------------------------------

27^{\frac{1}{5}

This has 1 as the numerator and 5 as the denominator.

1 can be ignored because any number to the 1 power is equal to itself.

5 is the root for 27

\sqrt[5]{27}

Hope this helps!! :)

Please let me know if you have any question

PilotLPTM [1.2K]4 years ago
6 0
It would be 5✔️27 but i’m not sure what the name of that root actually is
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