Question

can someone please help me with this :) i only have one more try to get it right and if not i get 0/10

Answer 1

Answer: $\sqrt[5]{27}$, fifthroot(27) [according to your picture, I think there will be no space between fifth and root]  

Step-by-step explanation:

concept to know: any exponent that is performed in fraction, the numerator will be the real exponent for the base, while the denominator will be the root

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$27^{\frac{1}{5}$

This has 1 as the numerator and 5 as the denominator.

1 can be ignored because any number to the 1 power is equal to itself.

5 is the root for 27

$\sqrt[5]{27}$

Hope this helps!! :)

Please let me know if you have any question

Answer 2

It would be 5✔️27 but i’m not sure what the name of that root actually is