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Tatiana [17]
3 years ago
10

Sully is riding a snowmobile on a flat, snow-covered surface with a constant velocity of 10 meters/second. The total mass of the

snowmobile, including Sully, is 280 kilograms. If Sully accelerates to a velocity of 16 meters/second over 10 seconds, what’s the force exerted by the snowmobile to accelerate? Use F = ma, where . 160 N 168 N 248 N 280 N 324 N
Physics
2 answers:
Gelneren [198K]3 years ago
7 0
Answer: 168N

16 - 10 = 6
6 / 10 = .6
F = 280 x .6 = 168
Svetradugi [14.3K]3 years ago
6 0
16 - 10 = 6
6 / 10 = .6 (this sign / means to divide)
F = 280 x .6 = 168
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A tank of volume 0.25 ft is designed to contain 50 standard cubic feet of air. The temperature is 80° F.Calculate the pressure i
slavikrds [6]

Answer:

The inside Pressure of the tank is 4499.12 lb/ft^{2}

Solution:

As per the question:

Volume of tank, V = 0.25 ft^{3}

The capacity of tank, V' = 50ft^{3}

Temperature, T' = 80^{\circ}F = 299.8 K

Temperature, T = 59^{\circ}F = 288.2 K

Now, from the eqn:

PV = nRT                      (1)

Volume of the gas in the container is constant.

V = V'

Similarly,

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Also,

The amount of gas is double of the first case in the cylinder then:

n' = 2n

\]frac{n'}{n} = 2

where

n and n' are the no. of moles

Now, from eqn (1) and (2):

\frac{PV}{P'V'} = \frac{nRT}{n'RT'}

P' = 2P\frac{T'}{T} = 2\times 2116\times \frac{299.8}{288.2} = 4499.12 lb/ft^{2}

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3 years ago
If the frog lands with a velocity equal to its average velocity and comes to a full stop 0.25s later, what is the frog’s average
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Answer:

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a=\frac{V-V0}{t}=\frac{0-V}{0.25}=-4V

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I assume the block plows into the bank of sand with a velocity of 6 m/s and comes to a stop in 2 s.

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