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natita [175]
3 years ago
13

You place a carrot in salt water for 24 hours. What do you observe about the carrot at the end of that time? Choose the two corr

ect answers. A. it will be shriveled B. it will be larger C. it will be firm D. it will be darker E. it will be limp
Chemistry
2 answers:
natka813 [3]3 years ago
8 0

Answer:

A & E

Explanation:

Salt water is a hypertonic solution, meaning it extracts water from whatever is placed in it. When a carrot loses water, it will most likely shrivel up and become limp.

olchik [2.2K]3 years ago
4 0
The answer is A and B because when a carrot is full of water the cells grow bigger and so does the carrot. When the concentration of water molecules inside the cells matches that outside, the carrot stops shriveling, and when you remove it from the water and taste it, it has a stronger flavor because it contains less water.
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Does anyone have answers of a worksheet called “ Intro to Graphs” Chemquest 2?
r-ruslan [8.4K]

Answer:

no

Explanation:

Because I have lost and I dont know where is the worksheet

8 0
2 years ago
Why do two oxygen atoms form a double covalent bond?
elena-s [515]

A lone oxygen atom has 6 electrons in its outer shell which is not very stable, whereas as full octet (8 outer shell electrons) is stable. In order to achieve this two oxygen atoms will share 4 electrons, each contributing 2 electrons. Since these electrons exist within the orbitals of both atoms, to oxygen atoms essentially achieve a full octet.

5 0
3 years ago
A gas tank contains 3 gases (N2, O2, and CO2). The total pressure of the gases is 825mmHg. If Pco2 = 125mmHg and Po2= 350mmHg, w
DedPeter [7]

Answer:

350mmHg

Explanation:

Use Dalton law

Total=P gas 1+p gas 2+ P gas 3

825=P1+350+125

825=P1+475

825-475= P1

P1= 350 mm Hg

3 0
2 years ago
Calculate pCl for the titration of 100.0mL of 0.1000 MCI with 0.1000 M
Anna71 [15]

the titration is the most important part in determining whether

4 0
3 years ago
How much ice (in grams) would have to melt to lower the temperature of 353 mL of water from 26 ∘C to 6 ∘C? (Assume the density o
Rashid [163]

Answer:

The mass of ice required to melt to lower the temperature of 353 mL of water from 26 ⁰C to 6 ⁰C is 85.4197 kg

Explanation:

Heat gain by ice = Heat lost by water

Thus,  

Heat of fusion + m_{ice}\times C_{ice}\times (T_f-T_i)=-m_{water}\times C_{water}\times (T_f-T_i)

Where, negative sign signifies heat loss

Or,  

Heat of fusion + m_{ice}\times C_{ice}\times (T_f-T_i)=m_{water}\times C_{water}\times (T_i-T_f)

Heat of fusion = 334 J/g

Heat of fusion of ice with mass x = 334x J/g

For ice:

Mass = x g

Initial temperature = 0 °C

Final temperature = 6 °C

Specific heat of ice = 1.996 J/g°C

For water:

Volume = 353 mL

Density (\rho)=\frac{Mass(m)}{Volume(V)}

Density of water = 1.0 g/mL

So, mass of water = 353 g

Initial temperature = 26 °C

Final temperature = 6 °C

Specific heat of water = 4.186 J/g°C

So,  

334x+x\times 1.996\times (6-0)=353\times 4.186\times (26-6)

334x+x\times 11.976=29553.16

345.976x = 29553.16

x = 85.4197 kg

Thus,  

<u>The mass of ice required to melt to lower the temperature of 353 mL of water from 26 ⁰C to 6 ⁰C is 85.4197 kg</u>

7 0
3 years ago
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