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Dmitriy789 [7]
3 years ago
10

Which of the following is in the correct order of boiling points for NaNO₃, CH₃OH, C₂H₆, and Ne?A) Ne < CH₃OH < C₂H₆ <

NaNO₃
B) NaNO₃ < CH₃OH < C₂H₆ < Ne
C) Ne < C₂H₆ < NaNO₃ < CH₃OH
D) Ne < C₂H₆ < CH₃OH < NaNO₃
E) C₂H₆ < Ne < CH₃OH < NaNO₃
Chemistry
1 answer:
Anestetic [448]3 years ago
3 0

Answer:

D

Explanation:

Me has the least boiling point because it has the weakest degree of intermolecular forces. The weak van Der Waals forces exist in C2H6. In CH3OH, there are strong hydrogen bonds which accounts for the higher boiling point. NaNO3 is an ionic compound, hence it has the highest boiling point among all the substances mentioned.

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** worth 20 points plus brainliest to whoever answer it correctly **
malfutka [58]

<u>Answer:</u> The correct answer is Option A.

<u>Explanation:</u>

To calculate the number of moles of a substance, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

We are given:

Given mass of fluorine = 6 grams

Now, to know the moles, we divide the given mass of fluorine by the atomic mass/molar mass of fluorine.

Thus, the correct answer is Option A.

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3 years ago
How many moles of helium is required to blow up a balloon to 87.1 liters at 74 C and 3.5 atm?
marshall27 [118]

Moles of helium is required to blow up a balloon to 87.1 liters at 74 C and 3.5 atm is  021.65 mole

Mole is the unit of amount of substances of specified elementary entities

According to the ideal gas law he number of moles of a gas n can be calculated knowing the partial pressure of a gas p in a container with a volume V at an absolute temperature T from the equation

n =pV/RT

Here given data is volume = 87.1 liters

Temperature = 74 °C means 347.15 k

Pressure = 3.5 atm

R = 0.0821

Putting this value in ideal gas equation then

n =pV/RT

n =  3.5 atm×87.1 liters / 0.0821 ×347.15 k

n = 021.65 mole

Moles of helium is required to blow up a balloon to 87.1 liters at 74 C and 3.5 atm is  021.65 mole

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