Answer:
The answers to the question are as follows
(a) The air temperature at the compressor exit is 557.56 K
(b) The back work ratio is 0.502
(c) The thermal efficiency is 0.482 or 48.2%
Explanation:
First we list out the given variables
Air temperature compressor inlet = 520 R
Air temperature turbine inlet = 2000 R
Pressure ratio of working fluid 10
The heat added to the air t the compressor is given by
Process 1 - 2 = = 1.93
Therefore T₂ = T₁ × 1.93 = 288.89 K × 1.93 = 557.56 K
(a) the air temperature at the compressor exit 557.56 K
(b) The back work ratio is given by
For the turbine we have = 1.93
which gives T₄ = = = 575.705 K
Therefore the back work ratio = = 0.502
(c) The thermal efficiency of a Brayton Cycle is given by
= 0.482
The cycle efficiency = 0.482 or 48.2%