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4 years ago

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Water of dynamic viscosity 1.12E-3 N*s/m2 flows in a pipe of 30 mm diameter. Calculate the largest flowrate for which laminar fl

ow can be expected (in lpm). What is the corresponding flowrate if it is an air flow (1.8E-5 N*s/m2 )

1 answer:

Naya [18.7K]4 years ago

7 0

Answer:

For water

Flow rate= 0.79128*10^-3 Ns

For Air

Flow rate =1.2717*10^-3 Ns

Explanation:

For the flow rate of water in pipe.

Area of the pipe= πd²/4

Diameter = 30/1000

Diameter= 0.03 m

Area= 3.14*(0.03)²/4

Area= 7.065*10^-4

Flow rate = 7.065*10^-4*1.12E-3

Flow rate= 0.79128*10^-3 Ns

For the flow rate of air in pipe.

Flow rate = 7.065*10^-4*1.8E-5

Flow rate =1.2717*10^-3 Ns

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Explanation:

a)

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In this problem, we have a system of two charges, so the total potential at a certain point will be given by the algebraic sum of the two potentials.

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$q_2=-3.00 \mu C=-3.00\cdot 10^{-6}C$

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Here we have to calculate the net potential at point B, located at

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The distance of charge 1 from point B is

$r_{1B}=\sqrt{(0.40)^2+(0.30)^2}=0.50 m$

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The work required to move a charged particle across a potential difference is equal to its change of electric potential energy, and it is given by

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Answer:

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C $_{\beta }$ = 98 wt% Sn - 2wt% Pb

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